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Rudik [331]
3 years ago
9

Parallelogram ABCD has vertex coordinates a(0,2) b (6,2) c (8,6 and d (2,6) write a rule to find the vertex coordinates of a par

allelogram PQRS that is smaller than , but similar to ABCD

Mathematics
1 answer:
Anastasy [175]3 years ago
8 0

Answer:  The rule is explained.


Step-by-step explanation:  As shown in the attached figure, ABCD is a parallelogram with vertices A(0,2), B(6,2), C(8,6) and D(2,6).

Suppose, we are to find the vertices of a parallelogram PQRS that is smaller than but similar to ABCD, then we can follow the following rule.

Let us consider a positive real number k. Then the new coordinates of smaller and similar parallelogram PQRS will be

Co-ordinates of P will be (k,2+k),

Co-ordinates of Q will be (6-k,2+k),

Co-ordinates of R will be (8-k,6-k)

and

co-ordinates of S will be (2+k,6-k).

Taking any positive real value of k, we will get a new, smaller parallelogram which will be similar to ABCD.



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Cost of each juice boxes is $ 0.68 and cost of each water bottle is $ 0.24

<em><u>Solution:</u></em>

Let "j" be the cost of each juice box

Let "w" be the cost of each bottles of water

<em><u>One teacher purchased 18 juice boxes and 32 bottles of water and spent $19.92</u></em>

Therefore, we frame a equation as:

18 x cost of each juice box + 32 x cost of each bottles of water = 19.92

18 \times j + 32 \times w = 19.92

18j + 32w = 19.92 ------ eqn 1

<em><u>The other teacher Purchased 14 Juice Boxes and 26 Boxes of water and spent $15.76</u></em>

Therefore, we frame a equation as:

14 x cost of each juice box + 26 x cost of each bottles of water = 15.76

14 \times j + 26 \times w = 15.76

14j + 26w = 15.76 ----------- eqn 2

<em><u>Let us solve eqn 1 and eqn 2</u></em>

<em><u>Multiply eqn 1 by 7</u></em>

126j + 224w = 139.44 -------- eqn 3

<em><u>Multiply eqn 2 by 9</u></em>

126j + 234w = 141.84 ---------- eqn 4

<em><u>Subtract eqn 3 from eqn 4</u></em>

126j + 234w = 141.84

126j + 224w = 139.44

( - ) --------------------

10w = 2.4

Divide both sides by 10

w = 0.24

<em><u>Substitute w = 0.24 in eqn 1</u></em>

18j + 32(0.24) = 19.92

18j + 7.68 = 19.92

18j = 12.24

Divide both sides by 18

j = 0.68

Thus cost of each juice boxes is $ 0.68 and cost of each water bottle is $ 0.24

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3 years ago
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