Easy
f(g(1))
evaluate g(1) then plug thatin for x in f(x)
g(1)=(x+2)/3
g(1)=(1+2)/3
g(1)=1
f(g(1))=
f(1)=(1)^2+3(1)+6
f(1)=1+3+6
f(1)=10
f(g(1))=10
Positive infinity and negative infinity
Answer:
81
Step-by-step explanation:
12/3 = 4
4 - 2 = 2
x = 2
using the order of operations, you would first have to do y + 3
y = 12
12 + 3 = 15
the equation simplified is 3 x 2 + 5 x 15
3 x 2 = 6
5 x 15 = 75
75 + 6 = 81
Answer: B
Step-by-step explanation:
