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Sergeeva-Olga [200]
3 years ago
8

Zack brought two new jet skis for $15,480 how will make 38 equal payments how much will each payment be?​

Mathematics
1 answer:
Free_Kalibri [48]3 years ago
8 0
15480/38=407.368 for each payment
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I need help with 38,39 and 40 please!
kodGreya [7K]

Answer:

It's 37. B 38. B 39. C 40. A

Step-by-step explanation:

4 0
3 years ago
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How do I solve for the blank
OLga [1]
Look at the problem and do it in order
3 0
3 years ago
Using appropriate properties find: <br> 6/5 × -5/7 -3/4 -5/7 × 4/5​
VARVARA [1.3K]

Answer:

1 and 4/35

Step-by-step explanation:

Use distribution property to solve:

6/5 × -5/7 -3/4 -5/7 × 4/5​ = -5/7 ( 6/5 - 3/4 ) x 4/5 = -5/7 ( 24/20 - 15/20 ) x 4/5 = -5/7 (-39/20) x 4/5 = 780 / 700 = 1 4/35

4 0
3 years ago
What is the area of the pentagon shown below a.27 square feet b. 58.5 c.85.5 d.117
Sergio [31]

Answer:

Option B, Area of pentagon = 58.5 Square feet

Step-by-step explanation:

The remaining part of the question is attached as image

Solution

Area of pentagon has a triangle and a trapezoid

Area of triangle = 0.5 *base *height = 0.5*9 *3 = 13.5  square feet

Area of trapezoid = Area of rectangle – 2* area of smaller triangles

= 9 ft * 6ft – ( 2 * 0.5 * 6 ft * (9 ft – 6ft) /2

= 54 – (1*6*1.5)

Area of pentagon = 13.5 + 45 = 58.5 Square feet

Hence, option B is correct

3 0
2 years ago
Discuss the continuity of the function on the closed interval.Function Intervalf(x) = 9 − x, x ≤ 09 + 12x, x &gt; 0 [−4, 5]The f
quester [9]

Answer:

It is continuous since \lim_{x\to 0^{-}} = f(0) = \lim_{x \to 0^{+} f(x)

Step-by-step explanation:

We are given that the function is defined as follows f(x) = 9-x, x\leq 0 and f(x) = 9+12x, x>0 and we want to check the continuity in the interval [-4,5]. Note that this a piecewise function whose only critical point (that might be a candidate of a discontinuity)  x=0 since at this point is where the function "changes" of definition. Note that 9-x and 9+12x are polynomials that are continous over all \mathbb{R}. So F is continous in the intervals [-4,0) and (0,5]. To check if f(x) is continuous at 0, we must check that

\lim_{x\to 0^{-}} = f(0) = \lim_{x \to 0^{+} f(x) (this is the definition of continuity at x=0)

Note that if x=0, then f(x) = 9-x. So, f(0)=9. On the same time, note that

\lim_{x\to 0^{-}} f(x) = \lim_{x\to 0^{-}} 9-x = 9. This result is because the function 9-x is continous at x=0, so the left-hand limit is equal to the value of the function at 0.

Note that when x>0, we have that f(x) = 9+12x. In this case, we have that

\lim_{x\to 0^{+}} f(x) = \lim_{x\to 0^{+}} 9+12x = 9. As before, this result is because the function 9+12x is continous at x=0, so the right-hand limit is equal to the value of the function at 0.

Thus, \lim_{x\to 0^{-}} = f(0) = \lim_{x \to 0^{+} f(x)=9, so by definition, f is continuous at x=0, hence continuous over the interval [-4,5].

5 0
3 years ago
Read 2 more answers
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