Step-by-step explanation:
Hope it helps you in your learning process.
Answer:
See explanation
Step-by-step explanation:
The surface area of the solid generated by revolving the region bounded by the graphs can be calculated using formula
![SA=2\pi \int\limits^a_b f(x)\sqrt{1+f'^2(x)} \, dx](https://tex.z-dn.net/?f=SA%3D2%5Cpi%20%5Cint%5Climits%5Ea_b%20f%28x%29%5Csqrt%7B1%2Bf%27%5E2%28x%29%7D%20%5C%2C%20dx)
If
then
![f'(x)=2x](https://tex.z-dn.net/?f=f%27%28x%29%3D2x)
and
![b=0\\ \\a=2](https://tex.z-dn.net/?f=b%3D0%5C%5C%20%5C%5Ca%3D2)
Therefore,
![SA=2\pi \int\limits^2_0 x^2\sqrt{1+(2x)^2} \, dx=2\pi \int\limits^2_0 x^2\sqrt{1+4x^2} \, dx](https://tex.z-dn.net/?f=SA%3D2%5Cpi%20%5Cint%5Climits%5E2_0%20x%5E2%5Csqrt%7B1%2B%282x%29%5E2%7D%20%5C%2C%20dx%3D2%5Cpi%20%5Cint%5Climits%5E2_0%20x%5E2%5Csqrt%7B1%2B4x%5E2%7D%20%5C%2C%20dx)
Apply substitution
![x=\dfrac{1}{2}\tan u\\ \\dx=\dfrac{1}{2}\cdot \dfrac{1}{\cos ^2 u}du](https://tex.z-dn.net/?f=x%3D%5Cdfrac%7B1%7D%7B2%7D%5Ctan%20u%5C%5C%20%5C%5Cdx%3D%5Cdfrac%7B1%7D%7B2%7D%5Ccdot%20%5Cdfrac%7B1%7D%7B%5Ccos%20%5E2%20u%7Ddu)
Then
![SA=2\pi \int\limits^2_0 x^2\sqrt{1+4x^2} \, dx=2\pi \int\limits^{\arctan(4)}_0 \dfrac{1}{4}\tan^2u\sqrt{1+\tan^2u} \, \dfrac{1}{2}\dfrac{1}{\cos^2u}du=\\ \\=\dfrac{\pi}{4}\int\limits^{\arctan(4)}_0 \tan^2u\sec^3udu=\dfrac{\pi}{4}\int\limits^{\arctan(4)}_0(\sec^3u+\sec^5u)du](https://tex.z-dn.net/?f=SA%3D2%5Cpi%20%5Cint%5Climits%5E2_0%20x%5E2%5Csqrt%7B1%2B4x%5E2%7D%20%5C%2C%20dx%3D2%5Cpi%20%5Cint%5Climits%5E%7B%5Carctan%284%29%7D_0%20%5Cdfrac%7B1%7D%7B4%7D%5Ctan%5E2u%5Csqrt%7B1%2B%5Ctan%5E2u%7D%20%5C%2C%20%5Cdfrac%7B1%7D%7B2%7D%5Cdfrac%7B1%7D%7B%5Ccos%5E2u%7Ddu%3D%5C%5C%20%5C%5C%3D%5Cdfrac%7B%5Cpi%7D%7B4%7D%5Cint%5Climits%5E%7B%5Carctan%284%29%7D_0%20%5Ctan%5E2u%5Csec%5E3udu%3D%5Cdfrac%7B%5Cpi%7D%7B4%7D%5Cint%5Climits%5E%7B%5Carctan%284%29%7D_0%28%5Csec%5E3u%2B%5Csec%5E5u%29du)
Now
![\int\limits^{\arctan(4)}_0 \sec^3udu=2\sqrt{17}+\dfrac{1}{2}\ln (4+\sqrt{17})\\ \\ \int\limits^{\arctan(4)}_0 \sec^5udu=\dfrac{1}{8}(-(2\sqrt{17}+\dfrac{1}{2}\ln(4+\sqrt{17})))+17\sqrt{17}+\dfrac{3}{4}(2\sqrt{17}+\dfrac{1}{2}\ln (4+\sqrt{17}))](https://tex.z-dn.net/?f=%5Cint%5Climits%5E%7B%5Carctan%284%29%7D_0%20%5Csec%5E3udu%3D2%5Csqrt%7B17%7D%2B%5Cdfrac%7B1%7D%7B2%7D%5Cln%20%284%2B%5Csqrt%7B17%7D%29%5C%5C%20%5C%5C%20%5Cint%5Climits%5E%7B%5Carctan%284%29%7D_0%20%5Csec%5E5udu%3D%5Cdfrac%7B1%7D%7B8%7D%28-%282%5Csqrt%7B17%7D%2B%5Cdfrac%7B1%7D%7B2%7D%5Cln%284%2B%5Csqrt%7B17%7D%29%29%29%2B17%5Csqrt%7B17%7D%2B%5Cdfrac%7B3%7D%7B4%7D%282%5Csqrt%7B17%7D%2B%5Cdfrac%7B1%7D%7B2%7D%5Cln%20%284%2B%5Csqrt%7B17%7D%29%29)
Hence,
![SA=\pi \dfrac{-\ln(4+\sqrt{17})+132\sqrt{17}}{32}](https://tex.z-dn.net/?f=SA%3D%5Cpi%20%5Cdfrac%7B-%5Cln%284%2B%5Csqrt%7B17%7D%29%2B132%5Csqrt%7B17%7D%7D%7B32%7D)
Answer:
M
Step-by-step explanation:
M
M
M
M
M
I
L
K
Answer:
customary system:
miles
ounces
metric system:
deciliters
kilometers
centigram
Step-by-step explanation:
Answer:
1 2/21
Step-by-step explanation:
We start out with:
3/7 + 2/3
In order to add them together, they must have an equal denominator. An easy way to find an equal denominator is the cross method. We divide 7 by 3 and 3 by 7, giving us a denominator of 21:
3/21 + 2/21
But what about the numerators? You do the same thing as before (multiplying by the other's denominator). Now we have:
9/21 + 14/21
We add both together (the denominator stays the same) and we get 23. 23/21 is correct but not in simplest form. We remove 21 from the numerator (because it is a whole) and finally get:
1 2/21!
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