<span>the number of nails in a bag of 120 that are less than 4.94 in. long will be found as follows: P(x<4.94)=P(z<Z) Z=(x-</span>μ<span>)/</span>σ where: x=4.94 in μ=5 in σ=0.03 thus Z=(4.94-5)/0.03 Z=-2 thus P(x<4.94)=P(z<-2)=0.0228
Thus the number of nails that are less than 4.94 will be: 0.0228×200=4.56~5 nails