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lorasvet [3.4K]
3 years ago
13

Plss hellpppp thank uu

Mathematics
2 answers:
Leviafan [203]3 years ago
4 0
The top row on the right:)

this number line includes any number to the left of 6 including 6!
Nikitich [7]3 years ago
4 0
It would be the top right, because this represents G is less than or equal to 6, like the equation shows. The line shows it could go on infinitely and the full circle shows it could be on 6.
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grandymaker [24]

Answer:

Step-by-step explanation:

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5 0
3 years ago
Read 2 more answers
ANSWER PLS URGENT VERY URGENT TYSM ik its a lot of questions but id really really be grateful for the help
anyanavicka [17]

Step-by-step explanation:

about circle R

arc angle MP = angle MRP = 78°

angle M = angle LMP.

according to the rules of inscribed angles, LMP is half of angle LRP.

LRP + MRP = 180° because together they cover the whole LM segment (half-circle).

LRP = 180 - MRP = 180 - 78 = 102°

so, LMP = angle M = 102/2 = 61°

also circle R (with arc ULNP)

the arc ULNP = arc UL + arc LN + arc NP = 160°

due to the congruent definition of JU and MP we know that arc UL = arc NP.

and we know arc LN = arc JM = 18°.

so,

160 = 2×arc NP + 18

142 = 2×arc NP

arc NP = 71° = arc UL

now, because arc MP + arc LP = 180 (half-circle),

arc MP = 180 - arc LP = 180 - arc LN - arc NP =

= 180 - 18 - 71 = 91°

about the circle R with 2 congruent chords :

the second answer : they are equidistant from R (the center of the circle).

about circle W

arc MK + arc KL = 180° (half-circle).

and we see

arc HL = arc KL = 53°.

so,

arc MK + 53 = 180°

arc MK = 180 - 53 = 127°

about circle M

arc QTS = 204°.

therefore, arc QRS = 360 - arc QTS = 360 - 204 =

= 156° = angle QMS.

according to the rules of inscribed angles

angle QTS = QMS/2 = 156/2 = 78°

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2 years ago
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In the diagram, a circle centered at the origin, a right triangle, and the Pythagorean theorem are used to derive the equation o
ehidna [41]

Answer:

(x – h)2 + (y – k)2 = r2

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(x – h)2 + (y – k)2 = r2

5 0
3 years ago
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