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Simora [160]
3 years ago
9

What is the quotient? StartFraction a minus 3 Over 7 EndFraction divided by StartFraction 3 minus a Over 21 EndFraction

Mathematics
2 answers:
kow [346]3 years ago
7 0

Answer:

the answer is -3

Step-by-step explanation:

Licemer1 [7]3 years ago
5 0

Answer:

The quotient is -3

Step-by-step explanation:

we have

\frac{a-3}{7}:\frac{3-a}{21}

Multiply in cross

\frac{(a-3)21}{(3-a)7}

Simplify

Remember that

\frac{21}{7}=3

substitute

\frac{(a-3)3}{(3-a)}

we know that

(3-a)=-(a-3)

substitute

\frac{(a-3)3}{-(a-3)}=-3

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8 times 8 times 8 times 8 as a power​
Dmitrij [34]

Answer:

tex]8^{4}[/tex]

Step-by-step explanation:

8^2 = 8 x 8 = 64

8^3 = 8 x 8 x 8 = 512

8^4 = 8 x 8 x 8 x 8 = 4096

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Elanso [62]
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The time to complete a standardized exam in the BYU-Idaho Testing Center is approximately normal with a mean of 70 minutes and a
leva [86]

Answer:

Step-by-step explanation:

Given that X the time to complete a standardized exam  in the BYU-Idaho Testing Center is approximately normal with a mean of 70 minutes and a standard deviation of 10 minutes.

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We have std deviation = 10

Hence 2 std deviations from the mean

= Mean ±2 std deviations

=70±20

= (50,90)

Below 50, 0.25 or 2.5% would complete the exam.

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3 years ago
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3 years ago
Read 2 more answers
Determine the values of \theta if sec\;\theta=-\frac{2}{\sqrt{3}}.
Masja [62]

Answer:

See below.

Step-by-step explanation:

So, we have:

\sec(\theta)=-2/\sqrt{3}

Recall that secant is simply the reciprocal of cosine. So we can:

\cos(\theta)=(\sec(\theta))^{-1}=(-2/\sqrt{3})^{-1}\\\cos(\theta)=-\sqrt{3}/2

Now, recall the unit circle. Since cosine is negative, it must be in Quadrants II and/or III. The numerator is the square root of 3. The denominator is 2. The whole thing is negative. Therefore, this means that 150 or 5π/6 is a candidate. Therefore, due to reference angles, 180+30=210 or 7π/6 is also a candidate.

Therefore, the possible values for theta is

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and

7π/6 + 2nπ

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3 years ago
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