Please help solve this system y=3x+15 and y =5x+9

All of them plz I need help if ur older Shouldnt be hard

vfiekz [6]

Answer:

The answer for number 1 would be 57 dollars and 80 cents

Number two would be little ceasars

Number 3 would be 75 dollars and 60 cent

Number 4 would be 40 dollars and 80 cent

Number 5 would be 110 dollars and 98 cents

Step-by-step explanation:

Because of you take 68 and times it by 15% which would be .15 you would get 10.2 you would then take 68 and subtract 10.2 from it and get 57.8

Number 2: take 7.50 times it by .3 and you get 2.25 then subtract 2.25 from 7.50 and you get 5.25 so even with the coupon little ceasars pizza is still 25cent cheaper

Number 3: add 42 to 28 and you get 70. 8% of 70 is 5.6 so add 5.6 to 70 and you have your answer of 75.60

Number 4: 35.48 is the price alone. Times that number by .15 and you get 5.322. Add 35.48 and 5.322 to get 40.802 but for money wise you just need the 40.80

Number 5: 118 one again is the price standing alone but 118 multiplied by .10 is 11.8 so subtract 11.8 from 118 and you get 106.2 but there is still a sales tax. So 106.2 times .045 or 4.5% would be 4.779, add that number to 106.2 and you get 110.979. Now the problem did not say anything about rounding but the 9 would make the 7 an 8 so of you do that you get 110.98.

So to help you in the future when dealing with percentages with discounts and tax’s. if it’s a discount once you times the original number by the percentage you subtract the sum from the original number. As for taxes you do the same process but instead of subtracting you add

5 0

3 years ago

Estimate the integral ∫6,0 x^2dx by the midpoint estimate, n = 6

Anettt [7]

Splitting up the interval [0, 6] into 6 subintervals means we have

$[0,1]\cup[1,2]\cup[2,3]\cup\cdots\cup[5,6]$

and the respective midpoints are $\dfrac12,\dfrac32,\dfrac52,\ldots,\dfrac{11}2$ . We can write these sequentially as ${x_i}^*=\dfrac{2i+1}2$ where $0\le i\le5$ .

So the integral is approximately

$\displaystyle\int_0^6x^2\,\mathrm dx\approx\sum_{i=0}^5({x_i}^*)^2\Delta x_i=\frac{6-0}6\sum_{i=0}^5({x_i}^*)^2=\sum_{i=0}^5\left(\frac{2i+1}2\right)^2$

Recall that

$\displaystyle\sum_{i=1}^ni^2=\frac{n(n+1)(2n+1)}6$
$\displaystyle\sum_{i=1}^ni=\frac{n(n+1)}2$
$\displaystyle\sum_{i=1}^n1=n$

so our sum becomes

$\displaystyle\sum_{i=0}^5\left(\frac{2i+1}2\right)^2=\sum_{i=0}^5\left(i^2+i+\frac14\right)$
$=\displaystyle\frac{5(6)(11)}6+\frac{5(6)}2+\frac54=\frac{143}2$

8 0

3 years ago

Solve for c.<br> a(b-c)=d

Lisa [10]

Answer:

D: c=(ab-d)/a

Step-by-step explanation:

a(b-c)=d

ab-ac=d

ab=ac+d

ab-d=ac

(ab-d)/a=c

5 0

3 years ago

Read 2 more answers

Find DY divided by DX by implicit differentiation y=sinxy

amm1812

Answer:

Step-by-step explanation:

$y = sin(xy)\\\frac{d}{dx}y=cos(xy)(\frac{d}{dx}(xy))\\ \frac{d}{dx}y = cos(xy)(y + x*\frac{d}{dx}y)\\ write \: \frac{d}{dx}y \: as\:y'\\y' = cos(xy)(y+xy')\\y' = ycos(xy) + xy'cos(xy) \\y'-xy'cos(xy) = ycos(xy)\\y'(1-xcos(xy)) = ycos(xy)\\\\y' = \frac{ycos(xy)}{1-xcos(xy)}$

6 0

3 years ago

What is an equation of the line that passes through the point (5,4)(5,4) and is parallel to the line 6x-5y=156x−5y=15?

Westkost [7]

Answer:

7x+y=0

x+6y=5

x+y=0

Step-by-step explanation:

5 0

3 years ago