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spin [16.1K]
4 years ago
13

Math problem plz solve asap

Mathematics
1 answer:
Sergeeva-Olga [200]4 years ago
8 0

Simplify √-y to √yi

3+ 2y = √yi

Square bot sides

(3 + 2y)^2 = -y

Expand

9 + 12y + 4y^2 = -y

Move all terms to one side

9 + 12y + 4y^2 + y = 0

Simplify 9 + 12y + 4y^2 + y to 9 + 13y + 4y^2

9 + 13y + 4y^2 = 0

Split the second term in 9 + 13y + 4y^2 into two terms

4y^2 + 9y + 4y + 9 = 0

Factor out common terms in the first two terms, then in the last two terms

y(4y + 9) + (4y + 9) = 0

Factor out the common term 4y + 9

(4y + 9)(y + 1) = 0

Solve for y

y = -9/4, -1

Check solution

when y = -9/4, the original equation; 3 + 2y = √-y does not hold true. We will drop y = -9/4 from the solution set.

Therefore,

<u>y = -1</u>

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Step-by-step explanation:

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Find the error &amp; find the correct answer 2In(x)=In(3x)-[In(9)-2In(3)] In(x^2)=In(3x)-[In(9)-In(9)] In(x^2)=In(3x)-0 In(x^2)=
Art [367]

Answer:

Error:lnx^2=ln 3x not ln\frac{3x}{0}

Solution:x=0 and 3

Step-by-step explanation:

We have to find the error and correct answer

Given:2ln x=ln(3x)-[ln9-2ln(3)]

lnx^2=ln(3x)-[ln9-ln3^2]

Using the formula

alog b=logb^a

lnx^2=ln(3x)-[ln9-ln9]

lnx^2=ln(3x)-0

lnx^2=ln(3x)

x^2=3x

x^2-3x=0

x(x-3)=0

Therefore, x=0 and x=3

But last step in the given solution

lnx^2=ln\frac{3x}{0}=\infty

It is wrong this property is used when

log m-log n then

log\frac{m}{n}

Hence, the student wrote  lnx^2=ln\frac{3x}{0}instead of lnx^2=ln3x and solution is given by

x=0 and x=3

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