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Anika [276]
3 years ago
14

Carbohydrates, such as glucose, are excellent sources of immediate energy for living organisms. More complex carbohydrates, such

as glycogen and starch, can also be used for the long term storage of energy. However, carbohydrates play other vital roles, too. Which of the following describes another common use for carbohydrates?
Biology
2 answers:
Finger [1]3 years ago
7 0
Proteins and carbs known as glycoproteins on the outside of a cell are used in cell signaling, the immune system, and even reproduction. Glycoproteins are very important in the body!
PilotLPTM [1.2K]3 years ago
7 0
  • Cellulose is used as a structural component in plant cell walls.

because Cellulose is used as a structural component in plant cell walls.

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Assessment timer and count Assessment items Item 5 At each step, a dichotomous key involves how many choices?
natita [175]

Answer:

Keys consist of a series of choices that lead the user to the correct name of a given item. "Dichotomous" means "divided into two parts". Therefore, dichotomous keys always give two choices in each step

6 0
4 years ago
Read 2 more answers
What causes an ionic bond to form between sodium and chlorine ?
Vera_Pavlovna [14]

Answer:

They combine as atoms, and separate as ions.

Explanation:

When sodium and chlorine atoms come together to form sodium chloride (NaCl), they transfer an electron. ... Because the sodium ion has a positive charge, and the chlorine ion has a negative charge, they are attracted to each other, and form an ionic bond.

3 0
3 years ago
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A hidden population has been discovered in Turkey. Researchers have calculated that 22% of the population have Uner Tan Syndrome
Rainbow [258]

Answer:

Thus, 50% of the population are are heterozygous carriers for this condition

Explanation:

Researchers have calculated that 22% of the population have Uner Tan Syndrome. This condition follows the recessive mode of inheritance.

22% have the condition = q² (genotypic frequency uu) = 22/100 = 0.22

using the formular p + q = 1, since q² = 0.22, q = √0.22 = 0.4690

Thus p = 1-q where  is 0.4690 = 1-0.4690

  p = 0.5310

Then p² = 0.5310² = 0.2820 = 28% (genotypic frequency of homozygous normal)

using the formula p² + 2pq + q² where 2pq is the genotypic frequency of the heterozygous carriers. Thus, we have

2 x 0.5310 x 0.4690 = 0.498 = 50%

Thus, 50% of the population are are heterozygous carriers for this condition

6 0
3 years ago
Biology will give brainliest
sesenic [268]

The codons that encodes amino acid serine are as follows:

  1. TCT,
  2. TCC,
  3. TCA,
  4. TCG,
  5. AGT,
  6. AGC
7 0
4 years ago
HELP ME ASAP PLEASE ANSWER
astraxan [27]

Rewrite what's noted

  • Red(RR)
  • white(rr)
  • Pink(Rr)

As pink and red are crossed white is out of business.

So

Share will be halved

  • 50% pink :50% red
  • 50% Rr:50% RR

Option D

8 0
2 years ago
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