Answer:
-m
Step-by-step explanation:
Answer:
The given functions are


The sine function has a standard period of
by definition. However, this might change if we use a factor as coefficient of the x-varible, but in this case we don't have that.
Therefore, the period of both trigonometric functions is
.
Now, the images of each function is the y-variable set values that defines each function.
So, the function
has an image defined by the set
. It's impotant to notice that the range of a standard function is [-1,1], however, in this case, the function was shifted 1 unit up and it was streched by a factor of 4, that's why the standard image changes to
.
About the second function
, the image set is
, because the function was streched by a factor of 2.
Additionally, the image attached shows the graph of the given functions.
Answer:
b=11
Step-by-step explanation:
4(b+24)=(12b+8)
4b+96=12b+8
-4. -4
96=8b+8
-8. -8
88=8b
88÷8=11
Answer:
There are many scenario's.
Step-by-step explanation:
1.4:5
2.4/5
3.4÷5
Answer:
slope = 2
Step-by-step explanation:
Calculate the slope m using the slope formula
m = (y₂ - y₁ ) / (x₂ - x₁ )
with (x₁, y₁ ) = (82, - 96) and (x₂, y₂ ) = (87, - 86)
m =
=
= 2