Question

steve is 6 years younger than twice Rebecca’s age. If the sum of Steve and Rebecca’s age is 30, how old is Steve and how old is Rebecca

Answer 1

Firstly , Let Rebecca age be R and Steve age be S

Steve is 6 years younger than twice Rebecca age

Since steve is younger, then we will be using subtraction as the order of operation

Since Rebecca age is twice

Then, R x 2

=2R

Steve is 6 years younger than twice of Rebecca age

Mathematically ,

$S=-2R - 6$  ---------------- equation 1

the sum of Steven and Rebecca age is 30

$R+S =30$------------------ equation 2

Solve equation 1 and equation 2 simultaneously

$S=2R-6\\S+R=30$

Substitute $S=2R-6$ into equation 2

$2R-6+R=30$

Collect like terms

$2R+R=30-6$

$3R=36$

Divide both sides by R

$\frac{3R}{3} =\frac{36}{3\\} \\R=12$

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