Answer:
By the Central Limit Theorem, the sampling distribution of the sample mean amount of money in a savings account is approximately normal with mean of 1,200 dollars and standard deviation of 284.6 dollars.
Step-by-step explanation:
Central Limit Theorem
The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean
and standard deviation
, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean
and standard deviation
.
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
Average of 1,200 dollars and a standard deviation of 900 dollars.
This means that 
Sample of 10.
This means that 
The sampling distribution of the sample mean amount of money in a savings account is
By the Central Limit Theorem, approximately normal with mean of 1,200 dollars and standard deviation of 284.6 dollars.
Answer:

Step-by-step explanation:

Step 1: Factor out the common term 

Step 2: Add the whole numbers

Step 3: Combine the fractions:

Step 4: Convert the improper fractions to mixed numbers

Step 5: Add the numbers

Therefore, the answer to the equation is
in fraction, and decimal; 
Answer: 15 grams
If he had 100 grams of candy bar, then 30% of that is 30 grams (since 30/100 = 30%). Cut this in half and we end up with 30/2 = 15.
Another way to find the answer is to multiply 50 and 0.30 which is the decimal form of 30%. So we have 50*0.30 = 15 which is the same answer.
I had to answer a question similar to that one on Math XL. This question was about renting a truck instead of needing a 48 mile taxi. (Took me a long time just to find the truck question, but I am giving you the truck help me answer the question, in hopes that it will help you.)
The cost of renting a truck from Hamilton Auto Rental is $47.60 per day plus $0.15 per mile. The expression 47.60 plus 0.15 m represents the cost of renting a truck for one day and driving it m miles. Evaluate 47.60 plus 0.15 m for m equals 120.
Substitute the numerical value for each variable into the expression and simplify the result.
I am sorry if that didn't help you, but it was the closest thing I could find to use to help you.