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aliina [53]
4 years ago
14

Need to now how to write this number5'392'029'004

Mathematics
2 answers:
kobusy [5.1K]4 years ago
7 0
5,392,029,004 is how you write it.
AleksAgata [21]4 years ago
5 0
Five billion three hundred ninety two million twenty nine thousand and four
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What is the volume of a cylinder, in cubic feet, with a height of 8 feet and a base
erma4kov [3.2K]

Answer:

see below

Step-by-step explanation:

The volume of a cylinder is given by

V = pi r^2 h

We know the diameter is 18 so the radius is 1/2 d = 1/2(18) = 9

V = pi (9)^2 (8)

V =648 pi

Letting pi = 3.14

V = 648(3.14)

V =2034.72

Rounding to the tenths place

V =2034.7 ft^3

If you use the pi button

V = 2035.75204

Rounding to the tenths place

V =2035.8

3 0
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What is (f–g)(x)?<br><br>f(x) = -3x2<br><br>g(x) = -3x2+9x
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Graph the system of equations. {x -y = 6,
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In which quadrant is the coordinate pair (-3, -4) located?
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3 years ago
The following data summarizes results from 939 pedestrian deaths that were caused by accidents . If one of the pedestrian deaths
olganol [36]

Answer:

Step-by-step explanation:

Hello!

The contingency table is attached.

The total of pedestrians is 909, not 939, there are 30 accidents less in the given data.

I've calculated the asked probabilities using a total of 909.

1. The probability that the pedestrian was intoxicated or the driver was intoxicated.

Two events are mutually exclusive when the occurrence of one prevents the occurrence of the other in one single performance of the experiment. (i.e there is no intersection between the events P(A∩B)=0)

When two events are mutually exclusive, the probability of the union of both elements is equal to the sum of their individual probabilities P(A∪B)= P(A) + P(B).

When the events aren't mutually exclusive, the probability of their union is equal to the summary of their probabilities minus the probability of the intersection between these two events P(A∪B)= P(A) + P(B) - P(A∩B)

Where:

∪ is the union of both events, in colloquial language represents "or"

∩ is the union of both events, or intersection of the events, in colloquial language represents "and"

In this case P(P₁ ∪ D₁) = P(P₁) + P(D₁) - P(P₁ ∩ D₁) = \frac{306}{909} + \frac{132}{909} - \frac{81}{909} = 0.393

P₁ and D₁ are not mutually exclusive

2. The probability of the pedestrian was intoxicated or the driver was not intoxicated.

These two events aren't mutually exclusive.

P(P₁ ∪ D₂)= P(P₁) + P(D₂) - P(P₁ ∩ D₂)= \frac{306}{909} +\frac{777}{909} *-\frac{225}{909}= 0.944

I hope it helps!

3 0
3 years ago
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