The x intercept occurs when y = 0.
0=(x+2)^2 - 1
1=(x+2)^2
Take the square root of both sides. Note that the sqrt of 1 is 1. Then solve for x.
1=x+2
-1=x
The x intercept is -1.
The y intercept occurs when x=0.
y=(0+2)^2 - 1
y=2^2 -1
y=4-1
y=3
The y intercept is 3.
Now, to find the vertex...
This parabola is currently in a format called the vertex form, which is:
f(x) = (x-h)^2 + k
where (h, k) is the vertex.
Therefore, the vertex is (-2, -1).
Answer:
11 packages
Step-by-step explanation:
24/6=4
44/4=11
Think of PEMDAS, or Please Excuse My Dear Aunt Sally. Which is Parentheses, Exponents, Multiplication and Division, and Addition and Subtraction in that order.
Answer:
11
Step-by-step explanation:
1.80m + 0.6s = 12.00
[substitute the value of m into the equation]
1.80×(3) + 0.6s = 12
5.4 + 0.6s = 12
[make s the subject of the formula]
0.6s = 12 - 5.4
0.6s = 6.6
[divide both sides of the equation by 0.6]
0.6s / 0.6 = 6.6 / 0.6
s = 11
To prove that 11 is correct
[substitute the value of m and s into the equation]
1.80m + 0.6m = 12.00
1.80×(3) + 0.6×(11) = 12.00
5.4 + 6.6 = 12.00
12.00 = 12.00
