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AfilCa [17]
4 years ago
6

Can someone help me ASAP this is kinda hard

Mathematics
2 answers:
bulgar [2K]4 years ago
8 0

Answer:

C. 7+2n=-3 n=-5

Step-by-step explanation:

By reading it out and typing it out simultaneously, you can find this.

Since it says seven added to, A and B are not options.

By adding 7+2(5) you get 17, by 7+10

By entering -5 to 7+2(-5)

You get -3 because 2(-5) is -10 and -10+7 is -3

So, C. 7+2n=-3 n=-5 is correct

abruzzese [7]4 years ago
7 0

Answer:

C

Step-by-step explanation:

translate everything from english to math

ex:

added is +

two time some number is 2*n

equals is =

so you get:

7 + 2*n = -3, solve and you get -5

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Rsm geo lol- no idea how to start or do it at all
jek_recluse [69]

Answer:

42, 138, and 138 degrees DON'T FORGET THE DEGREES SIGNS!!!!!

Step-by-step explanation:

Using vertical angles theorem, we can get another 42, 180-42, and 180-42.

So we have 42, 138, and 138

7 0
3 years ago
If f(x) = x2 – 2x, find:<br><br> f(6)=
creativ13 [48]

Answer:

0

Step-by-step explanation:

When x=6

f(6) =(6)2-2(6)=12-12=0

8 0
3 years ago
Read 2 more answers
State of the triangles in each pair of similar. If so, State how you know they are similar and complete the similarity statement
Vinil7 [7]

Answer:

  b.  not similar

Step-by-step explanation:

The given sides* have the ratio 30:39 = 10:13 in one triangle and the ratio 20:27 = 10:13.5 in the other triangle. Since these ratios are different, the triangles cannot be similar.

____

* These are the sides bracketing the vertical angles at T. If the triangles were similar, the three sides would have to have the ratios 10 : 13 : 13.5.

However, the geometry shown would require that the angle opposite side 13.5 in one triangle have the same measure as the angle opposite side 13 in the other triangle. That is not possible, so it is not possible for these triangles to be similar.

6 0
3 years ago
Distance between parallel lines y=3x+10 and y=3x-20
Alecsey [184]

1. Take an arbitrary point that lies on the first line y=3x+10. Let x=0, then y=10 and point has coordinates (0,10).


2. Use formula d=\dfrac{|Ax_0+By_0+C|}{\sqrt{A^2+B^2}} to find the distance from point (x_0,y_0) to the line Ax+By+C=0.


The second line has equation y=3x-20, that is 3x-y-20=0. By the previous formula the distance from the point (0,10) to the line 3x-y-20=0 is:

d=\dfrac{|3\cdot 0-10-20|}{\sqrt{3^2+(-1)^2}}=\dfrac{30}{\sqrt{10}}=3\sqrt{10}.


3. Since lines y=3x+10 and y=3x-20 are parallel, then the distance between these lines are the same as the distance from an arbitrary point from the first line to the second line.


Answer: d=3\sqrt{10}.

4 0
3 years ago
What is the GCF of the following terms?
Shalnov [3]
The greatest GCF would be
30x {y}^{2}
7 0
3 years ago
Read 2 more answers
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