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2 years ago

Brainliest if answered

Mathematics

2 answers:

Fantom [35]2 years ago

6 0

Answer:

attached pic

Step-by-step explanation:

sattari [20]2 years ago

4 0

Answer:

Hope This Helps!!

it's not perfect.. but we get the idea...

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Use the following table to determine P(X>4).

STatiana [176]

Answer:

0.11

Step-by-step explanation:

To get the probability above, we simply look for the events greater than 4, then add their probabilities

That is;

P(5) + P(6) + P(7)

So the probability in this case will be;

0.07 + 0.03 + 0.01 = 0.11

4 0

2 years ago

It's all on the picture please answer

LiRa [457]

Answer:

32+8k

Step-by-step explanation:

multiply both sides by the number outside parenthesis

6 0

2 years ago

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Given 3 and m are the roots of the quadratic equation 2x2 + kx - 15 = 0. Find the values of k and m.

velikii [3]

Answer:

If the roots of any equation are equal then it means that their Discriminant = 0

So, b²-4ac = 0

We have given the equation 2x² + kx + 2, where,

a = 2

b = k (we have to find the value)

c = 2

Then, b²-4ac=0

b² - 4(2)(2) = 0

b² - 16 = 0

b² = 16

√16 = 4

Hence the vue of k is 4.

Read more on Brainly.in - https://brainly.in/question/15922720#readmore

Step-by-step explanation:

hope it helps you ( ◠‿◠ )

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1 year ago

Students in miss moseley's fourth grade class

Tpy6a [65]

Answer:

what?

Step-by-step explanation:

6 0

2 years ago

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Apply Newton’s method to estimate the solution of x3 − x − 1 = 0 by taking x1 = 1 and finding the least n such that xn and xn +

ss7ja [257]

Solution :

Given

$f(x)=x^3-x-1, x_1=1$

$f'(x)=3x^2-1$

Let the initial approximation is $x_1 =1$

So by Newton's method, we get

$x_{n+1}=x_n-\frac{f(x_n)}{f'(x_n)},n=1,2,...$

$x_2=x_1-\frac{f(x_1)}{f'(x_1)}=1-\frac{1^3-1-1}{3(1)^2-1}=1.5$

$x_3=1.5-\frac{(1.5)^3-1.5-1}{3(1.5)^2-1}=1.34782608$

$x_4=1.34782608-\frac{(1.34782608)^3-1.34782608-1}{3(1.34782608)^2-1}=1.32520039$

$x_5=1.32520039-\frac{(1.32520039)^3-1.32520039-1}{3(1.32520039)^2-1}=1.32471817$

$x_6=1.32471817-\frac{(1.32471817)^3-1.32471817-1}{3(1.32471817)^2-1}=1.32471795$

$x_5 \approx x_6$ are identical up to eight decimal places.

The approximate real root is x ≈ 1.32471795

∴ x = 1.32471795

4 0

3 years ago