Shown here is the graph of which inequality? Please helpp!

Mathematics

1 answer:

riadik2000 [5.3K]4 years ago

4 0

Here, x-coordinate = 2
y - coordinate = 3

It would be: 2x + 3y ≥ 6

In short, Your Answer would be Option C

Hope this helps!

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Dose anybody know how to solve this problem

exis [7]

check the transformation template below, hmmm so to get the graph of "y" move to the right by 1 unit, we can simply make C = -1.

$y=\stackrel{A}{1}\log_2(\stackrel{B}{1}x+\stackrel{C}{0})+\stackrel{D}{0}\qquad \qquad y=\stackrel{A}{1}\log_2(\stackrel{B}{1}x+\stackrel{C}{1})+\stackrel{D}{0} \implies y=\log_2(x-1)$

now, the x-intercept is simply where the graph touches the x-axis, and when that happens y = 0, so

$\begin{array}{llll} \textit{Logarithm Cancellation Rules} \\\\ log_a a^x = x\qquad \qquad a^{log_a x}=x\leftarrow \textit{let's use this rule} \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \stackrel{y}{0}~~ = ~~\log_2(x-1)\implies 2^0=2^{\log_2(x-1)}\implies 2^0=x-1 \\\\\\ 1=x-1\implies 2=x~\hspace{10em}\stackrel{x-intercept}{(2~~,~~0)}$