(15 points) + (brainliest)

Solve the expression using pemdas (4+5)÷3×4

Dennis_Churaev [7]

1) you add the variables in the bracket

(4+5)÷3×4

9÷3×4

2) you multiply 3 by 4

9÷3×4

9÷12

3) now you divide 9 by 12

9÷12

=0.75

7 0

3 years ago

Read 2 more answers

How far is 10% of a 2000 kilometer trip

aleksandrvk [35]

Answer:
10 2000
1x200=
200

5 0

3 years ago

Write the equation of the line of best fit using the slope-intercept formula $y = mx + b$. Show all your work, including the poi

Dennis_Churaev [7]

Answer:

$y=\frac{5}{7}x+\frac{135}{7}$

Step-by-step explanation:

You only need two points on a line to find the equation for that line.

We are going to use 2 points that cross that line or at least come close to. You don't have to use the green points... just any point on the line will work. You might have to approximate a little.

I see ~(67.5,67.5) and ~(64,65).

Now once you have your points, we need to find the slope.

You may use $\frac{y_2-y_1}{x_2-x_1}$ where $(x_1,y_1) \text{ and } (x_2,y_2)$ are points on the line.

Or you can line up the points vertically and subtract then put 2nd difference over 1st difference.

Like this:

( 64 , 65 )

-( 67.5, 67.5 )

--------------------

-3.5 -2.5

So the slope is -2.5/-3.5=2.5/3.5=25/35=5/7.

Now use point-slope form to find the equation:

$y-y_1=m(x-x_1)$ where $m$ is the slope and $(x_1,y_1)$ is a point on the line.

$y-65=\frac{5}{7}(x-64)$

Distribute:

$y-65=\frac{5}{7}x-\frac{5}{7}\cdot 64$

Simplify:

$y-65=\frac{5}{7}x-\frac{320}{7}$

Add 65 on both sides:

$y=\frac{5}{7}x-\frac{320}{7}+65$

Simplify:

$y=\frac{5}{7}x+\frac{135}{7}$

6 0

3 years ago

Simplify this please

Ugo [173]

Answer:

$\frac{12q^{\frac{7}{3}}}{p^{3}}$

Step-by-step explanation:

Here are some rules you need to simplify this expression:

Distribute exponents: When you raise an exponent to another exponent, you multiply the exponents together. This includes exponents that are fractions. $(a^{x})^{n} = a^{xn}$

Negative exponent rule: When an exponent is negative, you can make it positive by making the base a fraction. When the number is apart of a bigger fraction, you can move it to the other side (top/bottom). $a^{-x} = \frac{1}{a^{x}}$ , and to help with this question: $\frac{a^{-x}b}{1} = \frac{b}{a^{x}}$ .

Multiplying exponents with same base: When exponential numbers have the same base, you can combine them by adding their exponents together. $(a^{x})(a^{y}) = a^{x+y}$

Dividing exponents with same base: When exponential numbers have the same base, you can combine them by subtracting the exponents. $\frac{a^{x}}{a^{y}} = a^{x-y}$

Fractional exponents as a radical: When a number has an exponent that is a fraction, the numerator can remain the exponent, and the denominator becomes the index (example, index here ∛ is 3). $a^{\frac{m}{n}} = \sqrt[n]{a^{m}} = (\sqrt[n]{a})^{m}$

$\frac{(8p^{-6} q^{3})^{2/3}}{(27p^{3}q)^{-1/3}}$ Distribute exponent

$=\frac{8^{(2/3)}p^{(-6*2/3)}q^{(3*2/3)}}{27^{(-1/3)}p^{(3*-1/3)}q^{(-1/3)}}$ Simplify each exponent by multiplying

$=\frac{8^{(2/3)}p^{(-4)}q^{(2)}}{27^{(-1/3)}p^{(-1)}q^{(-1/3)}}$ Negative exponent rule

$=\frac{8^{(2/3)}q^{(2)}27^{(1/3)}p^{(1)}q^{(1/3)}}{p^{(4)}}$ Combine the like terms in the numerator with the base "q"

$=\frac{8^{(2/3)}27^{(1/3)}p^{(1)}q^{(2)}q^{(1/3)}}{p^{(4)}}$ Rearranged for you to see the like terms

$=\frac{8^{(2/3)}27^{(1/3)}p^{(1)}q^{(2)+(1/3)}}{p^{(4)}}$ Multiplying exponents with same base

$=\frac{8^{(2/3)}27^{(1/3)}p^{(1)}q^{(7/3)}}{p^{(4)}}$ 2 + 1/3 = 7/3

$=\frac{\sqrt[3]{8^{2}}\sqrt[3]{27}p\sqrt[3]{q^{7}}}{p^{4}}$ Fractional exponents as radical form

$=\frac{(\sqrt[3]{64})(3)(p)(q^{\frac{7}{3}})}{p^{4}}$ Simplified cubes. Wrote brackets to lessen confusion. Notice the radical of a variable can't be simplified.

$=\frac{(4)(3)(p)(q^{\frac{7}{3}})}{p^{4}}$ Multiply 4 and 3

$=\frac{12pq^{\frac{7}{3}}}{p^{4}}$ Dividing exponents with same base

$=12p^{(1-4)}q^{\frac{7}{3}}$ Subtract the exponent of 'p'

$=12p^{(-3)}q^{\frac{7}{3}}$ Negative exponent rule

$=\frac{12q^{\frac{7}{3}}}{p^{3}}$ Final answer

Here is a version in pen if the steps are hard to see.

5 0

3 years ago

Find a counterexample to disprove the statement "The Associative Property is true for division."

MaRussiya [10]

The associative property makes it so whichever which way the numbers are the answer will be the same but as shown in the picture this isn't true for this statement because the answers become completely different depending on where the numbers are in the equation.
6 divided by 3 is NOT equal to 3 divided by 6 which disproves that property.

5 0

3 years ago