12/3 as verable expression

Pls solve quickly !!

Eva8 [605]

Answer:

Options A

Step-by-step explanation:

Properties of the graph given for the function 'g',

y-intercept of the function 'g' → y = -4

Minimum value of g(x) → y = -4 (Value of the function at the lowest point)

Roots of g(x) → x = -2, 2

At x = 4,

g(4) = 11

Another function is,

f(x) = -x² - 4x - 4

= -(x² + 4x + 4)

= -(x + 2)²

Properties of the function f(x) = -(x + 2)²,

y-intercept (at x = 0) of the function 'f',

y = -(x + 2)²

y = -4

Since, leading coefficient of the function is (-1) therefore, graph will open downwards and the maximum point will be its vertex.

Maximum value of the function 'f' = Value of the function at the vertex

Coordinates of vertex → (-2, 0)

Therefore, maximum value of 'f' = 0

Roots (at y = 0) of the function 'f' → x = -2

At x = 4,

f(4) = -(4 + 2)²

= -36

Therefore, Options A will be the correct option.

5 0

3 years ago

Claire is going to an amusement park. The price of admission into the park is $30, and once she is inside the park, she will hav

nydimaria [60]

Answer:

1. $66

2. 30 + 4r

Step-by-step explanation:

Let

Price of admission into the park=$30

Price of every ride in the park=$4

Number of rides =x

Total cost of going to the park= 30+4x

1. How much money would Claire have to pay in total if she goes on 9 rides

Total cost of going to the park= 30+4x

When x=9

=30+4x

= 30 + 4(9)

=30 + 36

=$66

2. How much would she have to pay if she goes on r rides?

When x=r

Total cost of going to the park= 30+4x

= 30 + 4(r)

=30 + 4r

4 0

3 years ago

Read 2 more answers

(-14x+14)1/2+14x use distributive property Help please

brilliants [131]

1/2(-14x + 14) + 14x

Distributive property.

-7x + 7 + 14x

Combine like terms.

7x + 7 (This is the simplified answer.)

7 0

4 years ago

The graph below models the value of a $20,000 car t years after it was purchased.

icang [17]

Answer:

Each time, t, is associated with exactly one car value, y.

Step-by-step explanation:

The concept being tested is functions.

The graph describe is a vertical parabola that opens downwards.

All vertical parabolas are functions because the pass the vertical line test.

In other words, each time, t, is associated with exactly one car value, y.

The correct answer is the second option.

4 0

4 years ago

Read 2 more answers

P(k)=a^k=2 3 4 find value of a that makes this is a valid probability distribution

Vesna [10]

Sounds like you're asked to find $a$ such that

$\displaystyle\sum_{k=2}^4\mathbb P(k)=\mathbb P(2)+\mathbb P(3)+\mathbb P(4)=1$

In other words, find $a$ that satisfies

$a^2+a^3+a^4=1$

We can factorize this as

$a^4+a^3+a^2-1=a^3(a+1)+(a-1)(a+1)=(a+1)(a^3+a-1)=0$

In order that $\mathbb P(k)$ describes a probability distribution, require that $\mathbb P(k)\ge0$ for all $k$ , which means we can ignore the possibility of $a=-1$ .

Let $a=y+\dfrac xy$ .

$a^3+a-1=\left(y+\dfrac xy\right)^3+\left(y+\dfrac xy\right)-1=0$
$\left(y^3+3xy+\dfrac{3x^2}y+\dfrac{x^3}{y^3}\right)+\left(y+\dfrac xy\right)-1=0$

Multiply both sides by $y^3$ .

$y^6+3xy^4+3x^2y^2+x^3+y^4+xy^2-y^3=0$

We want to find $x\neq0$ that removes the quartic and quadratic terms from the equation, i.e.

$\begin{cases}3x+1=0\\3x^2+x=0\end{cases}\implies x=-\dfrac13$

so the cubic above transforms to

$y^6-y^3-\dfrac1{27}=0$

Substitute $y^3=z$ and we get

$z^2-z-\dfrac1{27}=0\implies z=\dfrac{9+\sqrt{93}}{18}$
$\implies y=\sqrt[3]{\dfrac{9+\sqrt{93}}{18}}$
$\implies a=\sqrt[3]{\dfrac{9+\sqrt{93}}{18}}-\dfrac13\sqrt[3]{\dfrac{18}{9+\sqrt{93}}}$

6 0

4 years ago