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4 years ago

×+29=4 give me a basic rules

1 answer:

4 0

X is a number when added to 29 will result in the answer 4.

x + 29 = 4
Subtract 29 from each side.

x + 29 - 29 = 4 - 29
x = -25

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Montano1993 [528]

Answer:

Step-by-step explanation:

The range is the values of y that extend from the vertex downwards

The vertex = (- 2, - 1) → y = - 1

range is (- ∞, - 1 ]

7 0

3 years ago

If 4/5=4×1/5then 5/12=

-BARSIC- [3]

Then 5/12=5×1/12

I hope this helped :)
if not, please leave a comment below

4 0

3 years ago

Which of the choices best describes this arithmetic sequence? -2, 1, 4, 7, 10

n200080 [17]

Answer:

the best choice for the sequence is +3

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

100 points!! PLEASE HELP

algol [13]

Answer:

See below

Step-by-step explanation:

Parent function:

y = √x

Translation rule:

(x, y) → (x - 3, y + 1)

It will translate right 3 units and up 1 unit

The translated function is:

f(x) = $\sqrt{x - 3}$ + 1

Graph is attached where dotted blue is parent function and solid red is translated function

3 0

3 years ago

Read 2 more answers

pls help will give brainliest Rena used the steps below to evaluate the expression (StartFraction (x Superscript negative 3 Base

kaheart [24]

Answer:

First "order of operations" mistake: step 2

First arithmetic mistake: step 4

Step-by-step explanation:

As we understand Rena's work, she wants to simplify ...

$\left(\dfrac{x^{-3}y^{-2}}{2x^4y^{-4}}\right)^{-3}$

for x = -1 and y = 2.

Her work seems to be ...

Step 1

$\text{Substitute $x=-1$ and $y=2$ into the expression}\\\\\left(\dfrac{(-1)^{-3}2^{-2}}{2(-1)^42^{-4}}\right)^{-3}\qquad\text{no error}$

Step 2

$\text{Simplify the parentheses}\\\\\left(\dfrac{2^4}{2(-1)^4(-1)^32^2}\right)^{-3}=\left(\dfrac{2^2}{2(-1)^7}\right)^{-3}\qquad\text{order of operations error}$

Step 3

$\text{Evaluate the power to a power}\\\\\dfrac{2^{-6}}{2^{-3}(-1)^{21}}\qquad\text{no error}$

Step 4

$\text{Use reciprocals and find the value}\\\\\dfrac{1}{2^32^6(-1)^{21}}=\dfrac{1}{8\cdot 64\cdot (-1)}=\dfrac{-1}{512}\qquad\text{error: $2^3$ is used instead of $2^{-3}$}$

_____

So, the first arithmetic error is in Step 4. However, the order of operations requires exponents be evaluated first. Doing that makes step 2 look like ...

$\left(\dfrac{-\dfrac{1}{4}}{2(1)\dfrac{1}{16}}\right)^{-3}=(-2)^{-3}\qquad\text{proper Step 2}$

We expect your answer is supposed to be Step 4.

7 0

4 years ago