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3 years ago

Which of the choices best describes this arithmetic sequence? -2, 1, 4, 7, 10

Mathematics

2 answers:

olga nikolaevna [1]3 years ago

5 0

A1 = -2

An = an-1 + 3

n200080 [17]3 years ago

4 0

Answer:

the best choice for the sequence is +3

Step-by-step explanation:

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Here is a sketch of y=x^2+bx+c The curve intersects

atroni [7]

Answer:

y = 18 and x = -2

Step-by-step explanation:

y = x^2+bx+c To find the turning point, or vertex, of this parabola, we need to work out the values of the coefficients b and c. We are given two different solutions of the equation. First, (2, 0). Second, (0, -14). So we have a value (-14) for c. We can substitute that into our first equation to find b. We can now plug in our values for b and c into the equation to get its standard form. To find the vertex, we can convert this equation to vertex form by completing the square. Thus, the vertex is (4.5, –6.25). We can confirm the solution graphically Plugging in (2,0) :

y=x2+bx+c

0=(2)^2+b(2)+c

y=4+2b+c

-2b=4+c

b=-2+2c

Plugging in (0,−14) :

y=x2+bx+c

−14=(0)2+b(0)+c

−16=0+b+c

b=16−c

Now that we have two equations isolated for b , we can simply use substitution and solve for c . y=x2+bx+c 16 + 2 = y y = 18 and x = -2

4 0

3 years ago

Brian invests ?1900 into a savings account. The bank gives 3.5% compound interest for the first 2 years and 4.9% thereafter. How

Scorpion4ik [409]

let's check how much is it after 2 years firstly.

$\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &1900\\ r=rate\to 3.5\%\to \frac{3.5}{100}\dotfill &0.035\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{yearly, thus once} \end{array}\dotfill &1\\ t=years\dotfill &2 \end{cases} \\\\\\ A=1900\left(1+\frac{0.035}{1}\right)^{1\cdot 2}\implies A=1900(1.035)^2\implies A=2035.3275$

Brian invested the money for 6 years, so now let's check how much is that for the remaining 4 years.

$\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &2035.3275\\ r=rate\to 4.9\%\to \frac{4.9}{100}\dotfill &0.049\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{yearly, thus once} \end{array}\dotfill &1\\ t=years\dotfill &4 \end{cases}$

$\bf A=2035.3275\left(1+\frac{0.049}{1}\right)^{1\cdot 4}\implies A=2035.3275(1.049)^4 \\\\\\ A\approx 2464.54\implies \boxed{\stackrel{\textit{rounded up }}{A=2465}}$

4 0

3 years ago

What is the mean of 90, 55, 75, 60, 80, and 90?

ElenaW [278]

90+55+75+60+80+90=450
450/6=75

8 0

3 years ago

Read 2 more answers

If a person walks 1/2 a mile in each 1/4 hour, how far does he walk in 1 hour?

laila [671]

Answer:

2 miles

Step-by-step explanation:

1/2+1/2+1/2+1/2=1

5 0

3 years ago

Read 2 more answers

The function h(x) is given below:

g100num [7]

Step-by-step explanation:

The domain and range of a function and its inverse are inverted i.e. The domain of the function will become range of its inverse and the range of the function will become the domain of its inverse.

When representing the function in ordered pairs, the first values in the pair represents the domain and second values represent the range of the function.

h(x) = {3,5),(5,-7)(6,-9)(10,-12)(12,16)}

Domain of h(x) is: {3, 5, 6, 10, 12}

Range of h(x) is: (5, -7, -9, -12, 16}

So,

Domain of $h^{-1}(x)$ = Range of h(x) = (5, -7, -9, -12, 16}

Range of $h^{-1}(x)$ = Domain of h(x) = {3, 5, 6, 10, 12}

Therefore, $h^{-1}(x)$ will be represented as:

{(5,3), (-7,5), (-9, 6), (-12, 10), (16,12)}

It seems like you have made some error while writing the original function because of which we are not getting an exact match in the answer. However by looking at the answers, option B is the nearest most and seems the correct answer.

6 0

3 years ago