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ArbitrLikvidat [17]

3 years ago

5

Joseph is making a 6 letter password using the letters A,B,C,D,E, and F. How many different codes can Joseph make is each letter

can only be used once?

1 answer:

defon3 years ago

4 0

6 letters x 6 letter password = 36 possible combinations

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Simplify.<br> (-8V2)(+1/2V32)

erastovalidia [21]

Hello!!

$\rule{300}{5}$

$\huge\blue{{\fbox{\tt{ANSWER:-\:}}}}$

$-32$

$\huge\red{{\underline{\overline{\textbf{MY\:EXPLANATION~!}}}}}$

Apply rule: $(-a) = -a$

$(-8\sqrt{2}) = - 8\sqrt{2}$

$= -8\sqrt{2}~\frac{1}{2}\sqrt{32}$

$\sqrt{2}~\sqrt{32} =\sqrt{64}$

$= -8\sqrt{64}~\frac{1}2}$

$\sqrt{64} = 8$

$= -8$ · $8$ · $\frac{1}{2}$

Multiply the numbers: $-~8$ · $8= -64$

$=-64$ · $\frac{1}{2} = -32$

$= -32$

Hope It Helps. . .

#LearnWithBrainly

$\huge\blue{{\fbox{\tt{ANSWER:-\:}}}}$

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