Remark
The key step is just to subtract 5 from both sides. The pointed of the inequality still points away from the variable and towards the number. As long as that remains true, the correct answer can be found.
Solution
2.7 ≤ b + 5 Subtract 5 from both sides.
2.7 - 5 ≤ b
- 2.3 ≤ b Write with the variable on the left.
b ≥ - 2.3 <<<< answer
Answer:
33
Step-by-step explanation:
a right angle is 90 degress since the other side is 57 than ac must be 33
I don't understand the way you put the answeres because 58 is the largest number here yet its before .78 on f and g on plus the number occurs 2 times
Answer:
2.10 s, 10.40 s.
Step-by-step explanation:
We know that the height of the rocket is given by the function:
We are asked to find the time for which the height of the rocket will be 350 ft. So, for that moment, we know the height but we don't know the time; however, we know that the equation can help us to find the time, doing h=350:
The last is a quadratic equation, which can be put in the form 
and solved applying the formula:
So, let's put the equation on the form adding 
and subtracting 
to each side of the equation; the result is:
So, we note that a=16, b=-200, and c=350.
Then,
According to the equation, that are the times for which the height will be 350 ft; that is because the rocket is going to ascend and then to fail again to the ground.
Answer:
Least number of bus require for trip = 5 buses (Approx)
Step-by-step explanation:
Given:
Total number of classes = 9
Number of student in each class = 25
Number of teacher = 4
Number of chaperones = Double of teacher
Bus hold = 45 people
Find:
Least number of bus require for trip
Computation:
Total number of student = 9 × 25
Total number of student = 225
Number of chaperones = 4 × 2
Number of chaperones = 8
Total people = 225 + 8 + 4
Total people = 237
Least number of bus require for trip = Total people / Bus hold
Least number of bus require for trip = 237 / 45
Least number of bus require for trip = 5.266
Least number of bus require for trip = 5 buses (Approx)
