Answers:
k = 13The smallest zero or root is x = -10
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Work Shown:
note: you can write "x^2" to mean "x squared"
f(x) = x^2+3x-10
f(x+5) = (x+5)^2+3(x+5)-10 ... replace every x with x+5
f(x+5) = (x^2+10x+25)+3(x+5)-10
f(x+5) = x^2+10x+25+3x+15-10
f(x+5) = x^2+13x+30
Compare this with x^2+kx+30 and we see that k = 13
Factor and solve the equation below
x^2+13x+30 = 0
(x+10)(x+3) = 0
x+10 = 0 or x+3 = 0
x = -10 or x = -3
The smallest zero is x = -10 as its the left-most value on a number line.
The measure of angle 3 is 150 degrees
ANSWER
For Jamal statement to be true,

EXPLANATION
The given statement is:
ax + b = a(x + c)
We expand the left hand side to obtain,
ax + b = ax + ac
Subtract ax from from both sides of the equation.
b=ac
We know that, a≠0 , so we can divide through by 'a'.

1 hamper box, curated by Jithu can be contained 5 cupcakes.
<h3>Calculation:</h3>
The total amount of cupcakes =665 nos.
Jithu wants to create a gift box, each of which contains 6 cupcakes.
We have to see first, whether 665 could be equally distributed or not.
Hence, 665/6= 110.84 unit
It is seen that the number is in a fraction.so, It can be said that 665 cakes cannot be equally distributed to each gift pack carrying 6 cakes.
Hence, 110*6=660 cupcakes.
∴665-660= 5 cupcakes in one box
So, it is concluded that Jithu could be prepared 110 gift boxes containing 6 cakes each & 1 box containing 5 cupcakes.
Learn more about cake-related problems:
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Answer:
$300 income$250 + $100 = $350 expenses$300 - $350 = a loss of $50
Step-by-step explanation: