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Rina8888 [55]
2 years ago
8

As indicated below, write the equation of the line passing through the point (2,2) and perpendicular to the line whose equation

is y=x

Mathematics
1 answer:
Tcecarenko [31]2 years ago
7 0
The answer to the question

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Christine is riding her bicycle. She rides for 11.2 kilometers at a speed of 7 kilometers per hour. For how many hours does she
xxMikexx [17]

Answer:

1.6\ hours

Step-by-step explanation:

we know that

She rides for 11.2 kilometers at a speed of 7 kilometers per hour

Using proportion

Find how many hours does she ride

\frac{7}{1}\frac{km}{h} =\frac{11.2}{x}\frac{km}{h}\\ \\x=11.2/7\\ \\x=1.6\ hours

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2 years ago
A student bought 34 pencils for school.If he sharpened 16 of the pencils before school, what is his ratio of un-sharpened pencil
Diano4ka-milaya [45]
16/34, ratio is other words of fraction, also means 16out of 34
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3 years ago
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Thepotemich [5.8K]

Answer:

Step-by-step explanation:

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3 years ago
Veronica wants to buy a house that costs $249,900. She is going to make a 20% down payment. How
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▹ Answer

<em>$49,980</em>

▹ Step-by-Step Explanation

\frac{20}{100} * $249,900 \\\\= $49,980

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6 0
2 years ago
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A population has a standard deviation of 5.5. What is the standard error of the sampling distribution if the sample size is 81?
VladimirAG [237]

Answer:

\sigma = 5.5

And we have a sample size of n =81. We want to estimate the standard error of the sampling distribution \bar X and for this case we know that the distribution is given by:

\bar X \sim N(\mu ,\frac{\sigma}{\sqrt{n}})

And the standard error would be:

\sigma_{\bar x}= \frac{\sigma}{\sqrt{n}}

And replacing we got:

\sigma_{\bar x}=\frac{5.5}{\sqrt{81}}= 0.611

Step-by-step explanation:

For this case we know the population deviation given by:

\sigma = 5.5

And we have a sample size of n =81. We want to estimate the standard error of the sampling distribution \bar X and for this case we know that the distribution is given by:

\bar X \sim N(\mu ,\frac{\sigma}{\sqrt{n}})

And the standard error would be:

\sigma_{\bar x}= \frac{\sigma}{\sqrt{n}}

And replacing we got:

\sigma_{\bar x}=\frac{5.5}{\sqrt{81}}= 0.611

4 0
3 years ago
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