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GaryK [48]
3 years ago
15

The Temperature at 5:00 A.M. Is -38 F. The temperature rises 20 by 11:00 A.M. Use addition to find the temperature at 11:00 A.M.

Mathematics
1 answer:
GarryVolchara [31]3 years ago
8 0
-38F + 20F equals -18F
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2 years ago
(Algebra II ) What is the equation of y = x^3 with the given transformations? vertical compression by a factor of 1/7, horizonta
NNADVOKAT [17]
\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\

\begin{array}{rllll}
% left side templates
f(x)=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
y=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
f(x)=&{{  A}}\sqrt{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
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\end{array}  \bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks horizontally by  } {{  A}}\cdot {{  B}}\\
\bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\
\bullet \textit{ vertical shift by }{{  D}}\\
\qquad if\ {{  D}}\textit{ is negative, downwards}\\
\qquad if\ {{  D}}\textit{ is positive, upwards}
\end{array}

\bf ----------------------------\\
f(x)=x^3\textit{compression by }\frac{1}{7}\quad or\quad A=7
\\ \quad \\
f(x)=7x^3\impliedby \textit{8 units to the left, or }C=+8
\\ \quad \\
f(x)=7(x+8)^3\impliedby \textit{now, reflection over x-axis, means}
\\ \quad \\
f(x)=-7(x+8)^3\impliedby \textit{a negative leading term's coefficient}
6 0
3 years ago
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Mademuasel [1]

Answer:

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3 0
4 years ago
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