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My name is Ann [436]
3 years ago
8

Solve for x. \12x + 3 13x + 2 x = [?]

Mathematics
2 answers:
MissTica3 years ago
5 0

ANSWER:

As the given angles are alternate exterior angles, so they must've equal.

12x + 3 = 13x + 2

12x - 13x = 2 - 3

- x = - 1

x = 1.

Vsevolod [243]3 years ago
3 0

Answer:

x=7

Step-by-step explanation:

25x+5=180

      -5    -5

25x=175

/25    /25

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Simplify 5+10−2^3 <br> thanks in advance
andrey2020 [161]
5+10-2^3
= 7

Step by step:
5+10-2^3
= 15 - 2^3
= 15 - 8
= 7
8 0
3 years ago
A box contains 3 yellow, 2 red, 4 green and 3 black marbles. Two marbles are taken one after the other at random from the box. W
Nata [24]
I believe it's 2/10.
7 0
3 years ago
The owner of a small store buys coats for ​$45.00 each. Answer parts a and b. a. He sells the coats for ​$63.00 each. What perce
irga5000 [103]

Answer:

The purchase price is 71.4% of the sale price.

Step-by-step explanation:

1) 45 / 63 = 0.714

2) 0.714 * 100 = 71.4%

I didn't see part B.

7 0
3 years ago
Express the terms of the following geometric sequence recursively.
BabaBlast [244]

Answer:

The most correct option for the recursive expression of the geometric sequence is;

4. t₁ = 7 and tₙ = 2·tₙ₋₁, for n > 2

Step-by-step explanation:

The general form for the nth term of a geometric sequence, aₙ is given as follows;

aₙ = a₁·r⁽ⁿ⁻¹⁾

Where;

a₁ = The first term

r = The common ratio

n = The number of terms

The given geometric sequence is 7, 14, 28, 56, 112

The common ratio, r = 14/7 = 25/14 = 56/58 = 112/56 = 2

r = 2

Let, 't₁', represent the first term of the geometric sequence

Therefore, the nth term of the geometric sequence is presented as follows;

tₙ = t₁·r⁽ⁿ⁻¹⁾ = t₁·2⁽ⁿ⁻¹⁾

tₙ =  t₁·2⁽ⁿ⁻¹⁾ = 2·t₁2⁽ⁿ⁻²⁾ = 2·tₙ₋₁

∴ tₙ = 2·tₙ₋₁, for n ≥ 2

Therefore, we have;

t₁ = 7 and tₙ = 2·tₙ₋₁, for n ≥ 2.

4 0
3 years ago
Sole w - 12 = -3 using mental math
kotykmax [81]

Answer:

-15

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
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