Answer:
Given :An Internet survey was e-mailed to 6977 subjects randomly selected from an online group involved with ears. There were 1337 surveys returned.
To Find : Use a 0.01 significance level to test the claim that the return rate is less than 20%.
Solution:
n = 6977
x = 1337
We will use one sample proportion test



We are given that the claim is the return rate is less than 20%.

Formula of test statistic = 
= 
= 
Refer the z table
P(z<-1.85)=0.0332
Significance level = 0.01=α
Since p value > α
So, we accept the null hypothesis .
So,the claim that the return rate is less than 20% is false.
The answer is A. -3 and its a negative result cause that's how it is, like for ex, -15/3 = -5 or 15/-3 = -5 is a negative, and w<span>hen two positive numbers are divided, the answer is a positive number 15/3 = 5.</span>
Answer:
h = 2√3
Step-by-step explanation:
Using pythagorean's theorem:
a² + b² = c² such that
h² + 2² = 4²
h² = 16 - 4
h² = 12
h= √12
h = √ 4 * 3
h = 2 √3
Note:
I divided the base and made it 2.
The other slant side = 4