Let the number be x. Then according to the question,
Step 1 :- Adding 3
=> x + 3
Step 2 :- Multiply the sum by 2
=> 2×(x + 3)
Step 3 :- Subtract 6
=> 2(x +3) - 6
Answer:
7
Step-by-step explanation:
the constant of 6y+3 is 6y+3
14
When you sqaure a number you multiply it by itself once so it would be (3x3) + 5. Rmemeber PEMDAS, so you multiply 3x3 first to get 9 and then you add 5 to get 14.