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3 years ago

Which situation demonstrates the law of large numbers

Mathematics

1 answer:

sveticcg [70]3 years ago

4 0

Answer: Choice B

The more trials you do, the closer the empirical probability should get to the theoretical probability. It won't be a perfect match but it will likely be close enough so to speak. Note how 70/420 = 1/6.

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What is the side length of a 121 square centimeter launch pad

DIA [1.3K]

11 centimeters is the length of the launch pad

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3 years ago

Read 2 more answers

Un paralelogramo con una base de 13cm y una altura de 8cm, su área es de

svlad2 [7]

El área del paralelogramo con base de 13 centímetros y altura de 8 centímetros es 104 centímetros cuadrados.

El área del paralelogramo, en centímetros cuadrados, es igual al producto de su base por su altura, ambos en centímetros. En consecuencia, el área de la figura geométrica es la siguiente:

$A = (13\,cm)\cdot (8\,cm)$

$A = 104\,cm^{2}$

El área del paralelogramo con base de 13 centímetros y altura de 8 centímetros es 104 centímetros cuadrados.

Invitamos cordialmente a ver esta pregunta sobre paralelogramos: brainly.com/question/17205536

4 0

3 years ago

Find all polar coordinates of point P where P = ordered pair 3 comma negative pi divided by 3 .

jek_recluse [69]

Answer:

The all polar coordinates of P are:

(3 , -π/3) , (3 , 5π/3) , (-3 , 2π/3) , (-3 , -4π/3)

Step-by-step explanation:

* Lets study the polar coordinates of a point

- In polar coordinates there is an infinite number of coordinates

for a given point.

- The polar coordinates of a point (x , y) is (r , θ), where

r = √ ( x2 + y2 )

θ = tan-1 ( y / x )

# Ex: the following four points are all coordinates for the same point.

* (5 , π/3) = (5 , −5π/3) = (−5 , 4π/3) =(−5 , −2π/3)

- These four points only represent the coordinates of the point without

rotating more than once

- So the point (r,θ) can be represented by any of the following

coordinate pairs (r , θ + 2π n) and (−r , θ + (2n + 1) π), where n is

any integer.

* Now lets solve the problem

∵ P = (3 , -π/3)

∵ (r , θ + 2πn)

∴ r = 3 an d Ф = -π/3

- let n = 1

∴ P = (3 , -π/3 + 2π)

∴ P = (3 , 5π/3)

∵ P =(3 , -π/3)

∵ P = (-r , θ + (2n + 1) π)

Let n = 0

∴ P = (-3 , -π/3 + (2×0 + 1) π)

∴ P = (-3 , -π/3 + (0 + 1) π)

∴ P = (-3 , -π/3 + π)

∴ P = (-3 , 2π/3)

∵ P =(3 , -π/3)

∵ P = (-r , θ + (2n + 1) π)

Let n = -1

∴ P = (-3 , -π/3 + (2(-1) + 1) π)

∴ P = (-3 , -π/3 + (-2 + 1) π)

∴ P = (-3 , -π/3 + -π) = (-3 , -4π/3)

∴ P = (-3 , -4π/3)

5 0

2 years ago

The set of all Real numbers between 4 and 7 including 4

erik [133]

4,5,6,7 is your answer

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2 years ago

Pleaseeee helpppp i’m not sure what this one is also please explain thanksss

AURORKA [14]

I think acute but I’m really not sure

5 0

3 years ago