If xy=0 then assume taht x and/or y=0
remember differnce of 2 perfect squares
a^2-b^2=(a-b)(a+b)
factor
6x^2-24=0
6(x^2-4)=0
6(x^2-2^2)=0
6(x-2)(x+2)=0
set to zero
x-2=0
x=2
x+2=0
x=-2
x=2 and -2
A is answer
Sorry i don't know. I hope you get a answer soon
Answer:
Step-by-step explanation:
he bout 6 red rose
Answer:
64
Step-by-step explanation:
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Answer:
(12,10)
Step-by-step explanation:
