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RSB [31]
3 years ago
7

The semicircle shown at left has center X XX and diameter W Z ‾ ​WZ ​ ​​ start overline, W, Z, end overline. The radius X Y ‾ ​X

Y ​ ​​ start overline, X, Y, end overline of the semicircle has length 2 22. The chord Y Z ‾ ​YZ ​ ​​ start overline, Y, Z, end overline has length 2 22. What is the area of the shaded sector formed by obtuse angle W X Y WXYW, X, Y?
Mathematics
1 answer:
BabaBlast [244]3 years ago
7 0
Triangle XYZ is equilateral, so the central angle of the sector is 120°, or 2π/3 radians. The area of a sector of central angle β is given by
.. A = (1/2)r^2*β . . . . . . β in radians
Your sector's area is
.. A = (1/2)*2^2*(2π/3) = 4π/3 . . . . square units
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I am not understanding these problems. Help me, please?
yanalaym [24]

Answer:

I think I know the answer but not 100% sure

Step-by-step explanation:

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Step 2: After you get done, submit the answer and see what grade you get.

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3 years ago
Penny makes 5 liters of applesauce. She saves 0.24 liter for dinner and puts the rest in jars. If each jar holds 0.68 liter, how
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Answer:

Penny can fill eight jars.

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2 years ago
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Jakob is tiling a newly finished room.He estimates that he tiles about 9 square ft every 3/4 hour. About how many sq ft can he t
Ganezh [65]
Okay this is how I would figure this out:
I would take 9 divided by 3 and get 3, so he can tile abut 3 square ft. in 15 minutes.
Then, I would multiply 3 by 4 because there are 4 15 in an hour. I would get 12.
So it takes Jakob 1 hour to tile 12 square feet. 

Your answer is: He can tile about 12 square feet per hour.

Hope this helped :)
4 0
3 years ago
Suppose x=10 and y=10. what is x after evaluating the expression (y>= 10)||(x++ >10)? java
Mamont248 [21]
<span>Suppose x=10 and y=10. what is x after evaluating the expression (y>= 10)||(x++ >10)? java
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4 0
3 years ago
Please help! Find the equation of the line (graph provided in attached picture) Use exact numbers. y =_ x+_ ( _ represent blanks
Dennis_Churaev [7]

Answer:

y = \frac{3}{4}x - 2

Step-by-step explanation:

Equation of a line is given as y = mx + b

Where,

m = slope of the line = \frac{y_2 - y_1}{x_2 - x_1}

b = y-intercept, which is the value at the point where the line intercepts the y-axis. At this point, x = 0.

Let's find m and b to derive the equation for the line.

m = \frac{y_2 - y_1}{x_2 - x_1}

Use the coordinate pair of any two points on the line. Let's use the following,

(0, -2) = (x_1, y_1) => on the line, when x = 0, y = -2

(4, 1) = (x_2, y_2) => on the line, when x = 4, y = 1

Plug in the values and solve for m

m = \frac{1 - (-2)}{4 - 0}

m = \frac{1 + 2}{4}

m = \frac{3}{4}

b = -2 (the line intercepts the y-axis at this point)

Our equation would be =>

y = mx + b

y = \frac{3}{4}x + (-2)

y = \frac{3}{4}x - 2

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3 years ago
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