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RSB [31]
4 years ago
7

The semicircle shown at left has center X XX and diameter W Z ‾ ​WZ ​ ​​ start overline, W, Z, end overline. The radius X Y ‾ ​X

Y ​ ​​ start overline, X, Y, end overline of the semicircle has length 2 22. The chord Y Z ‾ ​YZ ​ ​​ start overline, Y, Z, end overline has length 2 22. What is the area of the shaded sector formed by obtuse angle W X Y WXYW, X, Y?
Mathematics
1 answer:
BabaBlast [244]4 years ago
7 0
Triangle XYZ is equilateral, so the central angle of the sector is 120°, or 2π/3 radians. The area of a sector of central angle β is given by
.. A = (1/2)r^2*β . . . . . . β in radians
Your sector's area is
.. A = (1/2)*2^2*(2π/3) = 4π/3 . . . . square units
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If u-ai + bj and v-ci + dj are vectors, then which of the following statements is not true?
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Answer:

Option C

Step-by-step explanation:

Given that u-ai + bj and v-ci + dj are vectors

We have dot product

u.v = (ai+bj).(ci+dj) hence inner product of u and v.  So option a is true

The dot product of u and v is a scalar is true because dot product is always a scalar

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The dot product of u and v is given by the expression ac+bd

True because we multiply corresponding i components and j components and add.

So only C is not true.

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3 years ago
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3 years ago
Justify each step. <br> x/3-7=11 <br> x/3=18<br> x=6
Nina [5.8K]
This is the steps for equation solving for the value of x,
x/3-7 = 11
now 7 goes to the other side of equation by changing the sign from - to +,
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now when we multiply both sides of equation with 3 or 3 goes to the other side of equation and multiply with 18 leaving x alone here for finding the value of x,
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3 years ago
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