Question

The curve y = |x|/(sqrt(5- x^2)) is called a bullet-nose curve. Find an equation of the tangent line to this curve at the point (2, 2)

Answer 1

Absolute value
at x=2, the absolute value thing is positive
do this one
$y=x \sqrt{5-x^2}$
the derivitive is
$\frac{dy}{dx}=\sqrt{5-x^2}- \frac{x^2}{ \sqrt{5-x^2} }$
so the slope at x=2 is
$\frac{dy}{dx}=\sqrt{5-2^2}- \frac{2^2}{ \sqrt{5-2^2} }$=-3

a point is (2,2)
point slope form
y-y1=m(x-x1)
y-2=-3(x-2)
or
y=-3x+8
das is de equation