1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
gulaghasi [49]
1 year ago
12

Solve the simultaneous equations y=2-5x y = x² – 2x – 8

Mathematics
1 answer:
Aloiza [94]1 year ago
8 0

Answer:

Step-by-step explanation:

sub equation 1 into 2

2-5x=x²-2x-8

0=x²-2x+5x-8-2

0=x²+3x-10

0=(x-2)(x+5)

x=2 or x=-5

sub x into equation 1

y=2-5(2)                            or        y=2-5(-5)

y=-8                                              y=27

You might be interested in
J3herjjeodbehi4vdue duehduehd7ehee
Pie

The account already has $278

If you add and then subract 278 then the value will be the same

Your answer is B

Hopw this helps

-GoldenWolfX✔

7 0
3 years ago
Read 2 more answers
Calculate the mean, median, mode, range, and 5 Number Summary of the following data set: 5,6,8,4,7,5,4,2,5,6,5,2,1,4
Artist 52 [7]

Answer:

mean = 4.57, median = 5 , mode = 5, range =7 ,

five number summary: Minimum value= 1 , First Quartile = 4, Median = 5

Third Quartile  = 6, Maximum value = 8

Step-by-step explanation:

First arrange the data in ascending order.

1,2,2,4,4,4,5,5,5,5,6,6,7,8

Mean = sum of all numbers / total numbers

         = 1+2+2+4+4+4+5+5+5+5+6+6+7+8 / 14

         = 64 / 14

         = 4.57

Median:

Since the given data is even number so, we can find median by taking mean of 2 middle numbers.

so the middle numbers are 7th and 8th  data i.e, 5 and 5

Median =(5+5)/2

           = 5

Mode:

The most repetitive number in the data set is mode

So Mode = 5

Range:

Range can be found by subtracting smallest number from largest number in the data set.

Smallest number  = 1, Largest number = 8

Range= Largest number - Smallest number

        = 8-1 = 7

Five no Summary

Minimum value= 1

First Quartile ( 25 % mark )= 4

Median = 5

Third Quartile (75 % mark) = 6

Maximum value = 8

First quartile can be found by : consider the data on left of the median and find median among them

Third quartile can be found by:  consider the data on right of the median and find median among them

7 0
3 years ago
–5(–11)=?????????? please help me and answer it
Alja [10]

Answer:

55

Step-by-step explanation:

-5 (- 11)

= 55

5 0
3 years ago
Read 2 more answers
304 students went on a field trip. seven buses were filled and 17 students traveled in cars. how many students were in each bus?
nlexa [21]
41 students
-
304: total students
17: riding in car
7: number of buses
-
304 - 17 = 287
287 divided by 7 = 41
7 0
4 years ago
If f(x) = x3 and g(x) = (x + 1)3, which is the graph of g(x)?
ale4655 [162]
As you can see below, in red is <span>g(x) = (x + 1)^3 and in blue is f(x)=x^3. Adding 1 to x moves the graph to the left by 1. 

Hope this was the answer you were looking for and I hope you have a great day!
</span>

6 0
3 years ago
Read 2 more answers
Other questions:
  • Using side lengths only ,could triangles be similar
    7·1 answer
  • By cutting away identical squares from each corner of a rectangular piece of cardboard and folding up the resulting flaps, an op
    5·1 answer
  • The graph below could be the graph of which exponential function?
    9·2 answers
  • What is the slope of y=-4
    14·1 answer
  • Solving systems of equations using substitution p=q+3 4p+3q= -30
    11·1 answer
  • Subtract t from w, divide the result by u, then subtract v from what you have.
    9·1 answer
  • Martha is making a quilt. She has 63 squares ready to sew together. She wants the quilt to be 9 rows long. How many squares will
    12·1 answer
  • 15/16 - 7/32 Also find the sum or difference <br> A.13/32 <br> B.23/32<br> C 3/4
    12·1 answer
  • Explain why the triangles are similar. Then find the value of x. ​
    14·1 answer
  • 40 Points please help
    5·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!