Hello :
f(x) = <span>a(x-k)²+k....... the point vertex is (h , k )
in this exercice : h = -3 and k = -1 s0 f(x) = a(x+3)²-1
find : a
but f(0)=8
a(0+3)² -1 = 8
9a-1=8
9a =9
a=1
f(x) =(x+3)²-1 =x²+6x+9-1
f(x) = x²+6x+8 .... (</span><span>the quadratic function in standard form )</span>
Answer:
x=11
Step-by-step explanation:
Simplifying X= 7+4
therefore x=11
Answer:log48
Step-by-step explanation:
3log4+log6-log8
log4^3 + log6 - log8
log(4x4x4)+log6-log8
log64 + log6 - log8
log((64x6) ➗ 8)
log(384 ➗ 8)
log48
You can check your factoring by multiplying them all out to see if you get the original expression. If you do, your factoring is correct; otherwise, you might want to try again
