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storchak [24]
3 years ago
6

An animal cage is holding 8 black cats and 11 white cats. All of them want to get out of the cage. The cage door is opened sligh

tly and two cats escape. What is the probability that both cats are black?
Mathematics
1 answer:
Deffense [45]3 years ago
4 0

Answer:

A cage holds 6 black cats and 9 white cats, if two cats escape what is the probability of both cats being white?

Step-by-step explanation:

This involves two events, each with their own probability. Because both the first AND the second have to happen for this problem, you will MULTIPLY the wo individual probabilities.

Total cats = 15, White cats = 9

Probability first escaped cat is white = 9/15

One white cat has now escaped, so we now have Total cats = 14, White cats = 8

Probability second escaped cat is white = 8/14

Now MULTIPLY because this is an AND probability problem. (9/15)(8/14) = 72/210 = 12/35

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What is the value of y in the equation 5x+2y=20, when x=0.3
salantis [7]
Y=5/2 should be the answer
5 0
3 years ago
The height of a parallelogram is 5 feet more than it's base. If the area of the parallelogram is 204 square feet, what is its ba
siniylev [52]
The base is x.
The height is 5 feet more than the base, so it's x+5.
The area of a parallelogram is the product of its base and its height. The area is 204 square feet.

x(x+5)=204 \\
x^2+5x=204 \\
x^2+5x-204=0 \\
x^2+17x-12x-204=0 \\
x(x+17)-12(x+17)=0 \\
(x-12)(x+17)=0 \\
x-12=0 \ \lor \ x+17=0 \\
x=12 \ \lor \ x=-17

The length of the base of a parallelogram must be a positive number, so x=12.

\hbox{the base:} \\ x=12 \\ \\
\hbox{the height:} \\ x+5=12+5=17

The base is 12 feet long, the height is 17 feet long.
8 0
3 years ago
I need #14 done by tomorrow around 9-10:00. Thank you so much if you do. God bless you :3
Vinvika [58]

Answer:

A) $ \frac{1}{5} $

B) - 5

C) Not Possible

D) 5

E) $ \frac{-1}{5} $

  • Step-by-step explanation:
  • All integers are rational numbers. But not all rational numbers are integers.
  • All whole numbers are integers. But not all integers are whole numbers.

I am a rational number but not an integer. Located on the right of 0.

This means that it should be a positive number. Since, it is a rational number but not an integer, it should be of the form $ \frac{p}{q} $.

From, the options $ \frac{1}{5} $ would fit this description.

I am a rational number and an integer but not a whole number.

This means that it should be a negative integer. Since, all positive integers and zero would be whole numbers. From the options, the answer would be -5.

I am a whole number but not an integer.

This is clearly not possible because all whole numbers are a subset of integers.

I am a rational number, a whole number and an integer.

This means it is a positive integer. 5 would fit this description.

I am a rational number but not an integer; located on the left side of 0.

This means it is a negative number. $ -\frac{1}{5} $ should be the answer.

3 0
3 years ago
An un known or changeable quantity is known as (an)???
Jobisdone [24]
Its called a variable
7 0
3 years ago
what is the smallest of 3 consecutive positive integers if the product of smaller two interfere is 5 less than 5 times the large
Lady_Fox [76]

Answer:

Two options:

5,6, and 7

-1,0,and 1

Step-by-step explanation:

Three consecutive natural numbers can be represented as n, n+1, and n+2.

The product of the smaller two would be n(n+1). The less than 5 times the larger is 5(n+2)-5.

Set them equal and solve by factoring:

n(n+1) = 5(n+2) -5\\n^2+n = 5n+10 -5\\n^2+n = 5n+5\\n^2 -4n-5=0\\(n-5)(n+1)=0

Set each factor equal to 0.

n-5==0 so n=5.

n+1=0 so n=-1.

This means the 3 consecutive numbers would be 5,6, and 7

OR

-1, 0 or 1.

8 0
3 years ago
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