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Lemur [1.5K]
3 years ago
15

store one is selling three notebooks for $5.13 store to is selling 5 notebooks for $8.40 store 3 7/8 notebooks for $14 in which

store are the notebooks the cheapest​
Mathematics
1 answer:
sdas [7]3 years ago
5 0

Answer:

store 2

Step-by-step explanation:

This is because store one sells notebook for 5.13. Store 2 sells one notebook for 1.68, and the last stores sells one notebook for 2 or 1.75. Meaning that store 2 sells it for cheap.

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The vertex formation of a parabola is x = 8(y- 1)2-76.
Gennadij [26K]

Answer:

\boxed{x=8y^2-16y-68}

Step-by-step explanation:

Hello, please consider the following.

x=8(y- 1)^2-76\\\\x=8(y^2-2y+1)-76\\\\x=8y^2-16y+8-76\\\\\boxed{x=8y^2-16y-68}

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

6 0
3 years ago
Read 2 more answers
Please help asap 30 pts
motikmotik

Answer:

20 or D.

Step-by-step explanation:

You simply plug in the values given for a and b:

4(5)+7(-3)+3(5)-2(-3) = 20-21+15+6=20

So, your answer is 20.

5 0
4 years ago
Read 2 more answers
Is 22 ounces equal to 6 pound
serious [3.7K]
NO

16 ounce = 1 pound

22 ounce = 1.375 pound ≠ 6 pound


7 0
3 years ago
HELP! Consider the function represented by the graph. On a coordinate plane, a straight line with a negative slope begins on the
ch4aika [34]

Answer:

{ x | x ≥ 0 }

Step-by-step explanation:

Given,

There is a straight line started from (0, 9) and passes through (8, 1),

∵ In the coordinate plan, the values of x are arranged in increasing order to the right side of the y-axis,

Thus, the line is defined for all real values of x greater than 0,

Hence, Domain of the line = All real numbers greater than equal to 0,

i.e. { x | x ≥ 0 }

Thus, FIRST OPTION is correct.

7 0
3 years ago
Read 2 more answers
In a class of 40 students, everyone has either a pierced nose or a pierced ear. The professor asks everyone with a pierced nose
ladessa [460]

Answer:3

Step-by-step explanation:

Given

There are total 40 students in a class

No of students with Pierced Nose n(N)=7

No of students with Pierced ear n(E)=36

and we know using sets

n\left ( N\cup E\right )=n\left ( E\right )+n\left ( N\right )-n\left ( N\cap E\right )

where n\left ( N\cup E\right )=Students either nose or ear Pierced

n\left ( N\cap E\right )=no of students having both nose and ear pierced

40=7+36-n\left ( N\cap E\right )

n\left ( N\cap E\right )=43-40=3

3 0
3 years ago
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