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pashok25 [27]
3 years ago
7

The width,w, of a rectangular garden is X -2 the area of the garden is X^3-2X-4 what is an expression for the length of the gard

en?
A. X^2-2x-2
B. X^2+2x-2
C. X^2-2x+2
D. X^2+2x+2
Mathematics
1 answer:
Elan Coil [88]3 years ago
6 0
A=wl \Rightarrow 
l=\frac{A}{w}
l - length, A - area, w - width

A=x^3-2x-4 \\
w=x-2 \\ \\
l=\frac{x^3-2x-4}{x-2}=\frac{x^3-2x^2+2x^2-4x+2x-4}{x-2}=\frac{x^2(x-2)+2x(x-2)+2(x-2)}{x-2}=\\
=\frac{(x^2+2x+2)(x-2)}{x-2}=x^2+2x+2

The answer is D.
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Help please! show work thanks
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Answers
b = 2.77 m
A = 43.0°
C = 111.1°

cosine law to find b

b^2 = a^2 + c^2 -2ac \cos B \\ \\
b = \sqrt{a^2 + c^2 -2ac \cos B} \\ \\
b = \sqrt{4.33^2 + 5.92^2 - 2(4.33)(5.92) \cos 25.9} \\
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b = 2.7708\ m

Find angle A with sine law

\displaystyle
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A = \sin^{-1} \left[ \frac{4.33 \sin 25.9}{2.7708}  \right]  \\ \\
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Find C with angles in triangle sum to 180

A + B + C = 180
C = 180 - A - B
C = 180 - 43.0467020 - 25.9
C = 111.1
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