Question

Which product of prime polynomials is equivalent to 8x3 – 2x?

Answer 1

2x2(2x+1)(2x-1) this is the answer I got.

Answer 2

Answer:

The factor form of the given polynomial is $2x(2x-1)(2x+1)$

Step-by-step explanation:

The given expression is

$8x^3-2x$

Taking out the common factor 2x.

$8x^3-2x=2x(4x^2-1)$

$8x^3-2x=2x((2x)^2-(1)^2)$

Using the algebraic formula:

$a^2-b^2=(a-b)(a+b)$

We get,

$8x^3-2x=2x(2x-1)(2x+1)$

All the factors are prime polynomial because they can not be factored further.

Therefore the factor form of the given polynomial is $2x(2x-1)(2x+1)$.