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Agata [3.3K]
4 years ago
15

20 hours put into degrees?

Mathematics
1 answer:
kondor19780726 [428]4 years ago
6 0

Answer:

<h2>Your answer is <u><em>300</em></u></h2>

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Divide    <br>a^2+7a+12/a+4
Ulleksa [173]
a^2+7a+12=a^2+3a+4a+12=a(a+3)+4(a+3)=(a+3)(a+4)

therefore:\\\\\frac{a^2+7a+12}{a+4}=\frac{(a+3)(a+4)}{a+4}=a+3
5 0
3 years ago
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The Normal model​ N(65, 2.5) describes the distribution of heights of college women​ (inches). Which of the following questions
Tema [17]

Answer:

a) 11.51% probability that a random college woman has a height of 68 inches or​ more

b) This height is 70.135 inches.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

The normal distribution has two parameters, which are the mean and the standard deviation.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 65, \sigma = 2.5

a. What is the probability that a random college woman has a height of 68 inches or​ more?

This is 1 subtracted by the pvalue of Z when X = 68. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{68 - 65}{2.5}

Z = 1.2

Z = 1.2 has a pvalue of 0.8849

1 - 0.8849 = 0.1151

11.51% probability that a random college woman has a height of 68 inches or​ more

b. To be in the Tall​ Club, a woman must have a height such that only​ 2% of women are taller. What is this​ height?

This weight is the 100-2 = 98th percentile, which is the value of X when Z has a pvalue of 0.98. So X when Z = 2.054.

Z = \frac{X - \mu}{\sigma}

2.054 = \frac{X - 65}{2.5}

X - 65 = 2.054*2.5

X = 70.135

This height is 70.135 inches.

6 0
4 years ago
What are the domain, range, and asymptote of h(x) = (0.5)x – 9?
Rzqust [24]

Let's solve for h

hx = 0.5x - 9

Step 1: Divide both sides by x.

hx/x = 0.5x - 9/ x

Answer = h = 0.5x - 9/ x

8 0
3 years ago
PLEASE HELP ASAP!!!
arlik [135]

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4 years ago
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Find the product and simplify: −2x3y2×2y5
Anna [14]
I think the answer to this problem would be -4x^3 y^7
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3 years ago
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