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devlian [24]
3 years ago
8

Product of 3 and 25 plus the product of 5 and 30? It has to be an expression

Mathematics
2 answers:
Yakvenalex [24]3 years ago
8 0

Answer:

3(25)+5(30)

Step-by-step explanation:

Product means multiplying 2 things together and expression means you do not solve the equation you just leave it be

Verdich [7]3 years ago
6 0
3 x 25 + 5 x 30
hope this helps!!
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Can someone please help me with this
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3 0
3 years ago
Write the product in standard form.<br>(2 - 3i)(2 + i)​
Stels [109]

Answer:

Brainelist?

Step-by-step explanation:

7-4i

just use a online calculator

8 0
4 years ago
Read 2 more answers
See figure in triangle PQR,ANGLE PQR=90°,segQS seg PR find x,y and z
e-lub [12.9K]

Answer:

x=4√5

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is your answer look it once

3 0
3 years ago
A number n is no less than -3. what is the inequality
vazorg [7]

Answer:

n ≥ -3

Step-by-step explanation:

If n can be <em>no less than</em> -3... then we know that n has to be bigger than or equal to -3.

This could also be said as <em>greater than or equal to</em> -3

Conveniently enough... there is a sign for <em>greater than or equal to</em> and it is ≥

6 0
3 years ago
Need help with homework
motikmotik

We have two points describing the diameter of a circumference, these are:

\begin{gathered} A=(-12,-4) \\ B=(-4,-10) \end{gathered}

Recall that the equation for the standard form of a circle is:

(x-h)^2+(y-k)^2=r^2

Where (h,k) is the coordinate of the center of the circle, to find this coordinate, we find the midpoint of the diameter, that is, the midpoint between points A and B.

For this we use the following equation:

M=(\frac{x_1+x_2_{}_{}}{2},\frac{y_1+y_2}{2})

Now, we replace and solve:

\begin{gathered} M=(\frac{-12+(-4)}{2},\frac{-4+(-10)}{2} \\ M=(\frac{-12-4}{2},\frac{-4-10}{2}) \\ M=(\frac{-16}{2},\frac{-14}{2}) \\ M=(-8,-7) \end{gathered}

The center of the circle is (-8,-7), so:

\begin{gathered} h=-8 \\ k=-7 \end{gathered}

On the other hand, we must find the radius of the circle, remember that the radius of a circle goes from the center of the circumference to a point on its arc, for this we use the following equation:

r^2=\Delta x^2+\Delta y^2

In this case, we will solve the delta with the center coordinate and the B coordinate.

\begin{gathered} r^2=((-4)-(-8))^2+((-10)-(-7)) \\ r^2=(-4+8)^2+(-10+7)^2 \\ r^2=4^2+(-3)^2 \\ r^2=16+9 \\ r^2=25 \\ r=5 \end{gathered}

Therefore, the equation for the standard form of a circle is:

\begin{gathered} (x-(-8))^2+(y-(-7))^2=25 \\ (x+8)^2+(y+7)^2=25 \end{gathered}

In conclusion, the equation is the following:

(x+8)^2+(y+7)^2=25

4 0
1 year ago
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