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andriy [413]
3 years ago
14

dawn has a rug with a perimeter of 32 feet the width of her rug is 6 feet what is the length in feet of dawns rug

Mathematics
1 answer:
puteri [66]3 years ago
7 0
6*2=12
32-12=20
20/2=10.
Perimeter is all the way around an object. So take 6 two times and minus that from 32. Answer of that divide by 2 to get the length. Length of one side is 10 ft.
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Answer:

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Step-by-step explanation:

a(a²+ b²)x² + b²x - a =0

Use the quadratic equation formula:

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1. Evaluate the discriminant D

D = b² - 4ac = b⁴ - 4a(a² + b²)(-a) = b⁴ + 4a⁴ + 4a²b²  = (b² + 2a²)²

2. Solve for x

\begin{array}{rcl}x & = & \dfrac{-b\pm\sqrt{D}}{2a}\\\\ & = & \dfrac{-b^{2}\pm\sqrt{(b^{2}+2a^{2})^{2}}}{2a(a^{2} + b^{2})}\\\\ & = & \dfrac{-b^{2}\pm(b^{2}+ 2a^{2})}{2a(a^{2} + b^{2})}\\\\x = \dfrac{-b^{2}+(b^{2} + 2a^{2})}{2a(a^{2} + b^{2})}&\qquad& x =\dfrac{-b^{2}-(b^{2} + 2a^{2})}{2a(a^{2} + b^{2})}\\\\x =\dfrac{-b^{2}+(b^{2} + 2a^{2})}{2a(a^{2} + b^{2})}&\qquad& x =\dfrac{-b^{2}-(b^{2} +2a^{2})}{2a(a^{2} + b^{2})}\\\\\end{array}

\begin{array}{rcl}x = \large \boxed{\mathbf{\dfrac{a}{a^{2} + b^{2}}}}&\qquad& x =\dfrac{-b^{2}-(b^{2} +2a^{2})}{2a(a^{2} + b^{2})}\\\\&\qquad& x =\dfrac{-2b^{2}- 2a^{2}}{2a(a^{2} + b^{2})}\\\\&\qquad& x =\dfrac{-2(a^{2}+ b^{2})}{2a(a^{2} + b^{2})}\\\\&\qquad& x =\large \boxed{\mathbf{-\dfrac{1}{a}}}\\\\\end{array}

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3 years ago
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Answer:

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Step-by-step explanation:

8 0
3 years ago
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Find the value of y...​
soldier1979 [14.2K]

Answer:

y=0

Step-by-step explanation:

Rewrite Evaluate Powers:

33^{2y-1}+3^{-1}+2*3^{y}*3^{-1}=1

Calculate:

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Solve using substitution:

(3^{y})^{2}*\frac{1}{3} +\frac{2}{3} *3^{y}=1     t=3^{y}

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y∉R

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2 years ago
Word Problems : Subtract 18 rupees 9 paise from 75 rupees 80 paise<br><br>Write In Step by Step ​
AlladinOne [14]

Answer:

Question

Answers

Related Questions

Subtract the following:

A) 18 rupees 9 paise from 75 rupees 80 paise.

B) 49 rupees 79 paise from 123 rupees 68 paise.

Answer

VerifiedVerified

139.5k+ views

17.4k+ likes

Hint: Use decimal concept.

We know that, 1 rupee = 100 paise. We can reframe these questions as follows:

18 rupees 9 paise from 75 rupees 80 paise

18 rupees 9 paise can be represented as 18.09 rupees and 75 rupees 80 paise can be represented as 75.80 rupees. Now, on subtracting we’ll get,

75.80−18.09−−−−−− 57.71

Which means 57 rupees 71 paise

49 rupees 79 paise from 123 rupees 68 paise

49 rupees 79 paise can be represented as 49.79 rupees and 123 rupees 68 paise can be represented as 123.68 rupees. Now, on subtracting we’ll get,

123.68 −49.79−−−−−− 73.89

Which means 73 rupees 89 paise.

Note: We can also perform the subtraction by making all units the same that are paise and then subtract.

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