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andriy [413]
3 years ago
14

dawn has a rug with a perimeter of 32 feet the width of her rug is 6 feet what is the length in feet of dawns rug

Mathematics
1 answer:
puteri [66]3 years ago
7 0
6*2=12
32-12=20
20/2=10.
Perimeter is all the way around an object. So take 6 two times and minus that from 32. Answer of that divide by 2 to get the length. Length of one side is 10 ft.
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A salesperson earns a salary of $700 per month plus 2% of the sales. Which inequality correctly represents the total sales if th
My name is Ann [436]

Answer:

C. x\geq 55000

Step-by-step explanation:  

Let x be the total monthly sales.

We have been given that a salesperson earns a salary of $700 per month plus 2% of the sales. The salesperson want to have a monthly income of at least $1800.  

This means that 700 plus 2% of total monthly sales should be greater than or equal to 1800. We can represent this information in an equation as:

700+(\frac{2}{100})x\geq 1800

700+0.02x\geq 1800

Let us solve our inequality to find the monthly sales (x).

Subtract 700 from both sides of our inequality.

700-700+0.02x\geq 1800-700

0.02x\geq 1100

Divide both sides of inequality by 0.02.

\frac{0.02x}{0.02}\geq \frac{1100}{0.02}

x\geq \frac{1100}{0.02}

x\geq 55000

Therefore, the total monthly sales must be greater than or equal to 55,000 and option C is the correct choice.



5 0
3 years ago
Please help with this paper!! asap please
neonofarm [45]
1 is L
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Look back at your notes if you have any.


7 0
3 years ago
Can someone help me on this pls? It’s urgent, so ASAP (it’s geometry)
GarryVolchara [31]

<u>Question 6</u>

1) \overline{AB} \cong \overline{BD}, \overline{CD} \perp \overline{BD}, O is the midpoint of \overline{BD}, \overline{AB} \cong \overline{CD} (given)

2) \angle ABO, \angle ODC are right angles (perpendicular lines form right angles)

3) \triangle ABO, \triangle CDO are right triangles (a triangle with a right angle is a right triangle)

4) \overline{BO} \cong \overline{OD} (a midpoint splits a segment into two congruent parts)

5) \triangle ABO \cong \triangle CDO (LL)

<u>Question 7</u>

1) \angle ADC, \angle BDC are right angles), \overline{AD} \cong \overline{BD}

2) \overline{CD} \cong \overline{CD} (reflexive property)

3) \triangle CDA, \triangle CDB are right triangles (a triangle with a right angle is a right triangle)

4) \triangle ADC \cong \triangle BDC (LL)

5) \overline{AC} \cong \overline{BC} (CPCTC)

<u>Question 8</u>

1) \overline{CD} \perp \overline{AB}, point D bisects \overline{AB} (given)

2) \angle CDA, \angle CDB are right angles (perpendicular lines form right angles)

3) \triangle CDA, \triangle CDB are right triangles (a triangle with a right angle is a right triangle)

4) \overline{AD} \cong \overline{DB} (definition of a bisector)

5) \overline{CD} \cong \overline{CD} (reflexive property)

6)  \triangle ADC \cong \triangle BDC (LL)

7) \angle ACD \cong \angle BCD (CPCTC)

8 0
2 years ago
A right cylinder has a radius of r inches and height of 2r inches.
Bess [88]

Answer:

the volume is 6.28r^{3}in^{3}

Step-by-step explanation:

This problem bothers on the mensuration of solid shapes, a cylinder.

Given data

Volume v =  ?

Radius r =  r in

Height h=   2r in

We are expected to solve for the volume of a cylinder, given the above data we can substitute it in the formula for volume of a cylinder to obtain our result

we know that the expression for the volume of a cylinder is

v= \pi r^{2} h

v= 3.142*r^{2} *2r\\v= 3.142*2r^{3} \\v= 6.28r^{3} in^{3} \\

Hence the volume in terms of the radius is 6.28r^{3}in ^{3}

6 0
3 years ago
The probability distribution for a game is shown in the table below.
nydimaria [60]

Given:

It is given that

Probability of winning $ 0 = \frac{3}{10}

Probability of winning $ 100 = \frac{1}{5}

Probability of winning $ 200 = \frac{1}{10}

Probability of winning $ 500 = \frac{2}{5}

To find the probability of not winning a cash prize.

Explanation:

Not winning cash prize = winning $ 0

So,

Probability of not winning a cash prize

= Probability of winning $ 0

= \frac{3}{10}

Therefore,

The probability of not winning a cash prize is \frac{3}{10}. Option D.

4 0
3 years ago
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