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Aleksandr-060686 [28]
3 years ago
6

To those who need points 4-9+5/6*33

Mathematics
2 answers:
son4ous [18]3 years ago
8 0

Answer:

22.5

Step-by-step explanation:

4-9+\dfrac{5}{6}\cdot 33= \\\\\\4-9+27.5= \\\\\\-5+27.5= \\\\\\22.5

Hope this helps!

bazaltina [42]3 years ago
5 0

Answer:

22.5

Step-by-step explanation:

4-9+5/6*33

-5+165/6

= 22.5

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What is the answer to -104=8x how do you find what x is
dybincka [34]
8x = -104 (I like to flip mine around like this, but it doesn't matter).
Now, you subtract 8 from both sides because you are doing the inverse.
-104 - 8 = -112
x=-112
Hope this helps!
Have a nice day!
7 0
3 years ago
A rhombus has sides 11cm long the shorter diagonal of the rhombus is 8cm long find the size of the smaller angles of the rhombus
ZanzabumX [31]

Answer:

42.64°

Step-by-step explanation:

Note: A rhombus has all its sides equal, its opposite angle are equal, its  has bigger and smaller diagonal, diagonal bisect the angles and diagonal bisect each other.

From the diagram attached,

sinθ = opposite/adjacent

sinθ  = 4/11

θ = sin⁻¹(4/11)

θ = 21.32

Therefore, from the diagram,

The smaller angle of the rhombus = 2θ

The smaller angle of the rhombus = (2×21.32)

The smaller angle of the rhombus = 42.64°

8 0
2 years ago
A quantity with an initial value of 600 decays exponentially at a rate of
Snowcat [4.5K]

Answer:

The value of the quantity after 87 months will be of 599.64.

Step-by-step explanation:

A quantity with an initial value of 600 decays exponentially at a rate of 0.05% every 6 years.

This means that the quantity, after t periods of 6 years, is given by:

Q(t) = 600(1 - 0.0005)^{t}

What is the value of the quantity after 87 months, to the nearest hundredth?

6 years = 6*12 = 72 months

So 87 months is 87/72 = 1.2083 periods of 6 years. So we have to find Q(1.2083).

Q(t) = 600(1 - 0.0005)^{t}

Q(1.2083) = 600(1 - 0.0005)^{1.2083} = 599.64

The value of the quantity after 87 months will be of 599.64.

8 0
3 years ago
the population of arizona is estimated go increase by 6.2% every year. if the population was 4.18 million in 2016 estimate popul
aleksklad [387]

Given:

a.) The population of Arizona is estimated to increase by 6.2% every year.

b.) The population was 4.18 million in 2016.

For us to be able to determine the population in 2022, we will be using the following formula:

\text{ P = P}_0e^{rt}

Where,

P = Total population after time (t)

P₀ = Starting population = 4.18 million

r = Growth rate (in decimal form) = 6.2%/100 = 0.062

t = time (in years) = 2022 - 2016 = 6 years

e = Euler's number = 2.71828182845

We get,

\text{ P = P}_0e^{rt}\text{ = (4,180,000)(}2.71828182845)^{0.062(6)}\text{ P = 6,063,645.861797897 }\approx\text{ 6,063,646}

Therefore, the population in 2022 will be approximately 6,063,646.

7 0
11 months ago
Find the limit. (If an answer does not exist, enter DNE.)<br> lim ( (1/x)-(1/lxl)) <br> x→0^+
jek_recluse [69]

Answer:

0

Step-by-step explanation:

The + on the zero means the limit as x approaches 0 from the right side

\lim_{x \to 0^{+} } (\frac{1}{x} - \frac{1}{|x|})\\ \lim_{x \to 0^{+} } (\frac{1}{x} - \frac{1}{x})\\ \lim_{x \to 0^{+} } (0)\\0

4 0
2 years ago
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