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Vinil7 [7]
3 years ago
9

How do you do this?? I don’t understand at all

Mathematics
2 answers:
AlladinOne [14]3 years ago
7 0

X=5 becuase if 7*3=21 then x*3=15 and 5 times 3 = 15



So the answer is 12

Rus_ich [418]3 years ago
4 0

so i believe that 21 shrinks down to 7 and then you find what multiplication can make 7 to 21 and the answer is 3 because of 7*3=21

then  you do the same to the other side which is 15 but instead you divide by 3 which gives you 5 so

x=5

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Nady [450]

-4v^3+11v^2-6v=-v(4v^2-11v+6)=-v(4v^2-8v-3v+6)\\\\=-v[4v(v-2)-3(v-2)]=-v(v-2)(4v-3)

4 0
3 years ago
Simplify the ratio 1:1.5
Rufina [12.5K]

Answer:

the answer is 2:3

Step-by-step explanation:

1/1.5=2/3

7 0
4 years ago
The table lists the heights (in centimeters) of preschool girls and boys on a playground. Heights of Preschool Boys (centimeters
Stells [14]

Answer:

B. The difference of the medians is about one-fourth the interquartile range of either data set

Step-by-step explanation:

Given the heights of preschool boys in cms

105.1 104.8 101.3 87 86.7 95 93.8 92.1 92.4 100

Arrange them in ascending order

86.7 87 92.1 92.4 93.8 95 100 101.3 104.8 105.1

Median = 93.8: Q1 = 87:Q3=101.3

IQR = Q3-Q1 = 4.3

Given the heights of preschool girls in cms

 85.2 90.3 99.6 98.6 97.5 101.7 102.9 89.4 107 92

Arrange them in ascending order

 85.2 89.4 90.3 92 97.5 98.6 99.6 101.7 102.9 107

Median = 97.5: Q1 = 89.4:Q3=101.7

IQR = 4.2

Differnce in the medians = 3.7

Diff in IQR = 0.1

B. The difference of the medians is about one-fourth the interquartile range of either data set because

0.4 = 4(0.1)

3 0
4 years ago
Determine the length of side QR in the following triangle
Jobisdone [24]

The length of the side QR in the task content can be determined as; 12.22cm.

<h3>What is the length of the third side QR?</h3>

It follows from the task content that 2 lengths and one included angle are given in the task content. It therefore follows that the length of side QR can be evaluated by the cosine rule as follows;

QR² = 13² + 4² - (2×4×13×cos70)

QR = √149.4

QR = 12.22cm

Read more on cosine rule;

brainly.com/question/23720007

#SPJ1

3 0
2 years ago
A bee flies at 9 feet per second directly to a flowerbed from its hive. The bee stays at the flowerbed for 13 ​minutes, and then
Usimov [2.4K]

Answer: 576 feet

Step-by-step explanation:

You have to do a little subtracting and a little interpreting to get the answer. First you must assume that the bee travels in a straight line. This is math so we can assume this is true, although thousands would disagree.

Second you must assume that because it is loaded with nectar that it travels at a slower rate (not an unreasonable assumption).

Third you have to assume that the distance there is the same distance as coming back. Again this is math. We can make this assumption.

Find the travelling time.

The bee spends 12 minutes hunting down the nectar in the flowerbed. Since it was away from the hive for a total of 16 minutes, the travelling time is

16min - 12min = 4 min

Convert the Minutes to seconds.

1 minute = 60 seconds

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Find the time each way.

The total time is 240 seconds, but it is not divided evenly.

Let the time there = t

Let the time back = 240 - t

The distances are the same.

r = 6 m/s

r1 = 4 m/s

t1 = t

t2 = 240 - t

dthere = dback

d = rate * time

6 m/s *t = 4 m/s (240 - t)      Remove the brackets on the right.

6 * t = 4*240 - 4t                  Combine the like terms on the right.

6t = 960 - 4t                         Add 4t to both sides

6t + 4t = 960 - 4t + 4t          Combine

10t = 960                              Divide both sides by 10

10t/10 = 960/10                    Do the division

t = 96                                    Time going to the flower bed

Find the distance

d = ?

r = 6 m/s

t = 96 second

d = r*t

d = 6 * 96 = 576 feet Answer

5 0
3 years ago
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