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riadik2000 [5.3K]
3 years ago
13

Help me with this question for brainliest please

Mathematics
1 answer:
Pepsi [2]3 years ago
8 0

Answer:

A

Step-by-step explanation:

We want to find the surface area, which will essentially just be the areas of all the figures given in the net.

We have two congruent triangles and 3 different rectangles.

<u>Triangles</u>:

The area of a triangle is denoted by: A = (1/2) * b * h, where b is the base and h is the height. The base here is 3 and the height is 4, so:

A = (1/2) * b * h

A = (1/2) * 3 * 4 = 6

Since there are two triangles, multiply 6 by 2: 6 * 2 = 12 cm squared

<u>Rectangles</u>:

The area of a rectangle is denoted by: A = b * h, where b is the base and h is the height.

The base of the leftmost rectangle is 4 and the height is 7, so:

A = b * h

A = 4 * 7 = 28

The base of the middle rectangle is 3 and the height is 7, so:

A = b * h

A = 3 * 7 = 21

The base of the rightmost rectangle is 5 and the height is 7, so:

A = b * h

A = 5 * 7 = 35

Add these together:

12 + 28 + 21 + 35 = 96 cm squared

The answer is thus A.

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Right triangles abc and dbc with right angle c are given below. If cos(a)=15,ab=12 and cd=2, find the length of bd.
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see the attached figure to better understand the problem

we have that

cos(A)=\frac{1}{5} \\ AB=12\ units\\ CD=2\ units

Step 1

<u>Find the value of AC</u>

we know that

in the right triangle ABC

cos (A)=(AC/AB)\\AC=AB*cos(A)

substitute the values in the formula

AC=12*(1/5)\\ AC=2.4\ units

Step 2

<u>Find the value of BC</u>

we know that

in the right triangle ABC

Applying the Pythagorean Theorem

AB^{2} =AC^{2}+BC^{2}\\ BC^{2}=AB^{2} -AC^{2}

substitute the values

BC^{2}=12^{2} -2.4^{2}\\BC^{2}= 138.24\\ BC=11.76\ units

Step 3  

<u>Find the value of BD</u>

we know that

in the right triangle BCD

Applying the Pythagorean Theorem

BD^{2} =DC^{2}+BC^{2}

substitute the values  

BD^{2} =2^{2}+11.76^{2}

BD=11.93\ units

therefore

<u>the answer is</u>

the length of BD is 11.93 units

8 0
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Read 2 more answers
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