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2 years ago

HELPPPP PRECALC WILL GIVE BRAINLIEST

Mathematics

1 answer:

kifflom [539]2 years ago

4 0

Answer:

500

600

500

Step-by-step explanation:

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Please help with Geometry homework!!! Will give brainliest and 50 points to whoever answers first!!!

liraira [26]

A. Is 2x
B. Is 2x+3
This shows the line and contracts it

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3 years ago

(MATH) What is the reason for each step in the solution of the inequality?

Rama09 [41]

Step-by-step explanation:

Inequalities are solved just like equations the only difference is that the inequality sign has to be considered.

We are writing the steps with reason

So,

1. Given

$-38-3(x+5)>6x-17$

2. Distributive property:

$-38-3x-15>6x-17$

3. Combine like terms

$-3x-53>6x-17$

4. Subtraction property of order

$-3x-53-6x>-17$

$-9x-53> -17$

5. Addition property of order

$-9x> -17+53$

$-9x>36$

6. Division property of order

$x$

Keywords: Inequality, Properties

Learn more about inequalities at:

#LearnwithBrainly

7 0

3 years ago

Find the point(s) on the ellipse x = 3 cost, y = sin t, 0 less than or equal to t less than or equal to 2pi closest to the point

Lady_Fox [76]

Answer and Step-by-step explanation:

The computation of points on the ellipse is shown below:-

Distance between any point on the ellipse

$(3 cos t, sin t) and (\frac{4}{3},0) is\\\\ d = \sqrt{(3 cos\ t - \frac{4}{3}^2) } + (sin\ t - 0)^2\\\\ d^2 = (3 cos\ t - \frac{4}{3})^2 + sin^2 t$

To minimize

$d^2, set\ f' (t) = 0\\\\2(3cos\ t - \frac{x=4}{3} ).3(-sin\ t) + 2sin\ t\ cos\ t = 0\\\\ 8 sin\ t - 16 sin\ t\ cos\ t = 0\\\\ 8 sin\ t (1 - 2 cos\ t) = 0\\\\ sin\ t = 0, cos\ t = \frac{1}{2} \\\\ t= 0, \ 0, \pi,2\pi,\frac{\pi}{3} , \frac{5\pi}{3}$

Now we create a table by applying the critical points which are shown below:

t $d^{2} = (3\ cos t - \frac{4}{3})^{2} + sin^{2}t$

0 $\frac{25}{9}$ <u />

<u /> $\pi$ $\frac{169}{9}$

$2\pi$ $\frac{25}{9}$

$\frac{\pi}{3}$ $\frac{7}{9}$

$\frac{5\pi}{3}$ $\frac{7}{9}$

When t = $\frac{\pi}{3}$ , x is $\frac{3}{2}$ and y is $\frac{\sqrt{3} }{2}$ . So, the required points are $(\frac{3}{2},\frac{\sqrt{3} }{2})$

When t = $\frac{5\pi}{3}$ , x is $\frac{3}{2}$ and y is $\frac{-\sqrt{3} }{2}$ . So, the required points are $(\frac{3}{2},\frac{-\sqrt{3} }{2})$

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3 years ago

A ramp that is being constructed must be 42 inches long and reach a ledge that is 21 inches tall. Which inverse trigonometric ra

Brut [27]

You are given the opposite side length and the hypotenuse, so use sine
choice a

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3 years ago

HELP i hate graphs grrrrrrrrrrrrr

sergeinik [125]

The slope of the line is -5/2.

To find the slope you would either use rise (-5) over run (2), or y2 - y1 over x2 - x1 (-4 - 1/ 3 - 1).

See graph below to show the entire equation for the line.

I hope this helps!

6 0

3 years ago