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4 years ago

The new figure after a transformation is performed is called the __________.

Mathematics

2 answers:

Luda [366]4 years ago

3 0

we know that

A figure before the transformation is called pre-image and the figure after a transformation is called image

therefore

<u>the answer is the option D</u>

Image

marshall27 [118]4 years ago

3 0

The figure being transformed is called the preimage, pre- meaning before. In this case, the resulting image after transformation is called D.image. The two figures before and after transformation retains the size and shape, except for the location and coordinates of the points.

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stiks02 [169]

Answer:QB = 1/2 QE

QC = CF

DE = 2AB

Step-by-step explanation: hope it works

8 0

3 years ago

What conclusions can be made about the amount of money in each account if f represents Molly's account and g represents her brot

Nat2105 [25]

Answer:

(b) is true

Step-by-step explanation:

Given

Molly

$a = 500$ --- starting balance

$m = 10$ --- monthly rate

Her brother

$a = 100$ ---- starting balance

$r = 10\%$ --- annual rate

Required

Determine which option is true

First, we calculate her brother's function.

The function is an exponential function calculated as:

$y = ab^x$

Where $b = 1 + r$

So, we have:

$y = ab^x$

$y = 100 *(1 + 10\%) ^x$

$y = 100 *(1 + 0.10) ^x$

$y = 100 *(1.10) ^x$

Hence:

$g(x) = 100 *(1.10) ^x$

Next, we calculate Molly's function (a linear function)

The monthly function is:

$y = mx + a$

So, we have:

$y = 10x + 500$

Annually, the function will be:

$y = 10x*12 + 500$

$y = 120x + 500$

So, we have:

$f(x) = 120x + 500$

At this point, we have:

$f(x) = 120x + 500$ ---- Molly

$g(x) = 100 *(1.10) ^x$ ---- Her brother

<u>Next, we test each option</u>

(a): Molly's account will have a faster rate of change over [32,40]

We calculated Molly's function to be:

$y = 120x + 500$

The slope of a linear function with the form: $y = mx + b$ is m

By comparison:

$m = 120$

Since Molly's account is a linear function, the rate of change over any interval will always be the same; i.e.

$m = 120$

For his brother:

Rate of change is calculated using:

$m = \frac{g(b) - g(a)}{b - a}$

$m = \frac{g(40) - g(32)}{40 - 32}$

$m = \frac{g(40) - g(32)}{8}$

Calculate g(40) and g(32)

$g(x) = 100 *(1.10) ^x$

$g(40) = 100 * 1.10^{40} =4526$

$g(32) = 100 * 1.10^{32} = 2111$

So, we have:

$m = \frac{4526 - 2111}{8}$

$m = \frac{2415}{8}$

$m = 302$

By comparison: $302 > 120$

Hence, her brother's account has a faster rate over [32,40]

(a) is false

(b): Molly's account will have a slower rate of change over [24,30]

$m = 120$ --- Molly's rate of change

For his brother:

$m = \frac{g(b) - g(a)}{b - a}$

$m = \frac{g(30) - g(24)}{30 - 24}$

$m = \frac{g(30) - g(24)}{6}$

Calculate g(30) and g(24)

$g(x) = 100 *(1.10) ^x$

$g(40) = 100 * 1.10^{30} =1745$

$g(32) = 100 * 1.10^{24} = 985$

So, we have:

$m = \frac{g(30) - g(24)}{6}$

$m = \frac{1745 - 985}{6}$

$m = \frac{760}{6}$

$m = 127$

By comparison: $127 > 120$

Hence, Molly's account has a slower rate over [24,30]

(b) is false

(c): Molly's account will have a slower rate of change over [0,4]

$m = 120$ --- Molly's rate of change

For his brother:

$m = \frac{g(b) - g(a)}{b - a}$

$m = \frac{g(4) - g(0)}{4 - 0}$

$m = \frac{g(4) - g(0)}{4}$

Calculate g(4) and g(0)

$g(x) = 100 *(1.10) ^x$

$g(4) = 100 * 1.10^4 =146$

$g(0) = 100 * 1.10^{0} = 100$

So, we have:

$m = \frac{g(4) - g(0)}{4}$

$m = \frac{146 - 100}{4}$

$m = \frac{46}{4}$

$m = 11.5$

By comparison: $120>11.5$

Hence, Molly's account has a faster rate over [0,4]

(c) is false

4 0

3 years ago

he value of y varies directly with the value of x. When y = 32.5, x = 5. What is the value of y when x = 10? A) 1.5 B) 2.2 C) 37

xz_007 [3.2K]

Answer:

D) 65

Step-by-step explanation:

The formula for direct variation is

y = kx

where k is the constant of variation.

If we know y=32.5 and x=5, we can substitute in to calculate k

32.5 = k * 5

Divide each side by 5

32.5/5 = k

6.5 = k

So the equation is

y = 6.5k

Given x =10

y = 6.5*10

y = 65

7 0

3 years ago

Read 2 more answers

Which expression is equivalent to StartRoot 128 x Superscript 8 Baseline y cubed z Superscript 9 Baseline EndRoot? Assume y grea

zepelin [54]

The expression √(128x⁸y³z⁹) is equivalent to the expression 8x⁴yz⁴ √(2yz). Then the correct option is C.

The missing options are given below.

<h3>What is an equivalent expression?</h3>

The equivalent is the expressions that are in different forms but are equal to the same value.

The expression is given below.

⇒ √(128x⁸y³z⁹)

Then the expression is given below.

⇒ √[(64 × 2)(x⁴)²(y²y)(z⁸z)]

⇒ 8x⁴yz⁴ √(2yz)

Then the correct option is C.

More about the equivalent link is given below.

brainly.com/question/889935

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4 0

2 years ago

Which of the following is not an example of like terms? A. 2 and –6 B. 2b and –6b C. 2b and 2

Serggg [28]

I think it would be c

7 0

3 years ago

Read 2 more answers