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3 years ago

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Jason noticed that his house number is exactly divisible by 7. His friend Sam pointed out that it is also divisible by 18. If hi

s house number is a 4-digit number, find the smallest number that could be his house number.

1 answer:

Anon25 [30]3 years ago

8 0

I think the answer is 1008

Step-by-step explanation:

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Greta has 8 stickers. She splits them evenly among e envelopes. Write an expression that shows how many stickers are on each env

ohaa [14]

Answer:

8/e= s(stickers)

Step-by-step explanation:

When a question is asking for split, it means division.

7 0

3 years ago

Find the mean and the median of this data set: 8, 6, 5, 3, 41, 7, 4, 2

german

Answer:

5.5 is the median, and the mode is 10.625

Step-by-step explanation:

Median means the number in the middle, since there is an even ammount of numbers, it comes down to 5 and 6 and in the middle of that is 5.5

mode is when you add all of the numbers together and divide it by how many numbers it has and you have your answer

Pls mark brainliest :)

7 0

3 years ago

Help me please find the area of the rectangle.recall that area=length . Width

Lelechka [254]

Answer:

1/35 sq. ft.

Step-by-step explanation:

Area = 3/35 x 1/3

= 1/35 sq. ft.

Hope it helps.

;)

8 0

2 years ago

Read 2 more answers

The area of a triangle is 30 square feet. If<br> the base is 4 feet, then what is the height?

ExtremeBDS [4]

Height=15

Explanation:
Area of a triangle= 1/2base x height
Plug in information
30=1/2 x 4 x h
Solve 1/2 x 4 = 2
30= 2 x h
Divide both side by two
30/2=2 x h/2
Solve:
15= h

6 0

3 years ago

The probability that a student has a Visa card (event V) is .73. The probability that a student has a MasterCard (event M) is .1

snow_lady [41]

We assumed in this answer that the question b is, Are the events V and M independent?

Answer:

(a). The probability that a student has either a Visa card or a MasterCard is<em> </em> $\\ P(V \cup M) = 0.88$ . (b). The events V and M are not independent.

Step-by-step explanation:

The key factor to solve these questions is to know that:

$\\ P(V \cup M) = P(V) + P(M) - P(V \cap M)$

We already know from the question the following probabilities:

$\\ P(V) = 0.73$

$\\ P(M) = 0.18$

The probability that a student has both cards is 0.03. It means that the events V AND M occur at the same time. So

$\\ P(V \cap M) = 0.03$

The probability that a student has either a Visa card or a MasterCard

We can interpret this probability as $\\ P(V \cup M)$ or the sum of both events; that is, the probability that one event occurs OR the other.

Thus, having all this information, we can conclude that

$\\ P(V \cup M) = P(V) + P(M) - P(V \cap M)$

$\\ P(V \cup M) = 0.73 + 0.18 - 0.03$

$\\ P(V \cup M) = 0.88$

Then, <em>the probability that a student has either a Visa card </em><em>or</em><em> a MasterCard is </em> $\\ P(V \cup M) = 0.88$ .<em> </em>

Are the events V and M independent?

A way to solve this question is by using the concept of <em>conditional probabilities</em>.

In Probability, two events are <em>independent</em> when we conclude that

$\\ P(A|B) = P(A)$ [1]

The general formula for a <em>conditional probability</em> or the probability that event A given (or assuming) the event B is as follows:

$\\ P(A|B) = \frac{P(A \cap B)}{P(B)}$

If we use the previous formula to find conditional probabilities of event M given event V or vice-versa, we can conclude that

$\\ P(M|V) = \frac{P(M \cap V)}{P(V)}$

$\\ P(M|V) = \frac{0.03}{0.73}$

$\\ P(M|V) \approx 0.041$

If M were independent from V (according to [1]), we have

$\\ P(M|V) = P(M) = 0.18$

Which is different from we obtained previously;

That is,

$\\ P(M|V) \approx 0.041$

So, the events V and M are not independent.

We can conclude the same if we calculate the probability

$\\ P(V|M)$ , as follows:

$\\ P(V|M) = \frac{P(V \cap M)}{P(M)}$

$\\ P(V|M) = \frac{0.03}{0.18}$

$\\ P(V|M) = 0.1666.....\approx 0.17$

Which is different from

$\\ P(V|M) = P(V) = 0.73$

In the case that both events <em>were independent</em>.

Notice that

$\\ P(V|M)*P(M) = P(M|V)*P(V) = P(V \cap M) = P(M \cap V)$

$\\ \frac{0.03}{0.18}*0.18 = \frac{0.03}{0.73}*0.73 = 0.03 = 0.03$

$\\ 0.03 = 0.03 = 0.03 = 0.03$

3 0

4 years ago