The excess reactant when 4.35 g of hydrogen reacts with 30.75g of hydrogen iodide is hydrogen
<h3>calculation</h3>
write the equation for the reaction
H2(g) + I2 (g) → 2HI (g)
find the mole of each reactant
moles = mass/molar mass
moles of H2= 4.35 g/2 g/mol= 2.175 moles
moles o I2 = 30.75 g/ 254 g/mo=0.1211 moles
0.1211 moles of I2 reacted with 0.1211 moles of H2 but there are more moles of H2 there Hydrogen was in excess
Answer:
a chain of decays that result in a stable nucleus
Explanation:
Decay series is a series of decay in which radioactive element is decomposed in different elements until it produces one stable atom.
We can use a ratio to solve this question. Lets refer to the amount formed by the formula as a serving
1 serving needs 3/8 gal
We want to create 7/9 servings extra, so
1 + 7/9 = 16/7
1 : 3/8
16/7 : x
1/(3/8) = (16/7) / x
8 / 3 = 16x / 7
x = 7/6
He needs to use 7/6 gallons of water.
Answer:
Option C = 1.72 mol
Explanation:
Given data:
Mass of KF = 100 g
Moles of KF = ?
Solution:
First of all we have to calculate the molar mass of KF.
Molar mass of KF = 39.0983 g/mol + 18.998403 g/mol
Molar mass of KF = 58. 0967 g/mol
Formula:
Number of moles = mass/molar mass
Number of moles = 100 g/ 58.0967 g/mol
Number of moles = 1.72 mol