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Troyanec [42]
3 years ago
11

10. Copper(i) bromide reacts with magnesium metal: 2 CuBr + Mg → 2 Cu + MgBrz

Chemistry
2 answers:
velikii [3]3 years ago
5 0

Answer:

72.6 grams

Explanation:

I got this answer through stoichiometry.  For every 1 mole of Mg, 2 moles of CuBr are consumed.  Because of this, multiply the moles of Mg by 2.  Then, convert moles to grams.

Inessa05 [86]3 years ago
3 0

Answer:

72.611g

Explanation:

Step1:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

2CuBr + Mg → 2Cu + MgBr2

Step 2:

Let us calculate the mass of Mg in 0.253 mole of Mg. This is illustrated below:

Molar Mass of Mg = 24g/mol

Mole of Mg = 0.253 mole

Mass of Mg =?

Mass = number of mole x molar Mass

Mass of Mg = 0.253 x 24

Mass of Mg = 6.072g

Step 3:

Let us calculate the mass of CuBr and the mass of Mg that reacted from the balanced equation. This is illustrated below:

Molar Mass of CuBr = 63.5 + 80 = 143.5g/mol

Mass of CuBr from the balanced equation above = 2 x 143.5 = 287g

Molar Mass of Mg = 24g/mol

Step 4:

The mass of CuBr consumed by 0.253 mole ( i.e 6.072g) of Mg can be obtained as follow:

From the balanced equation:

2CuBr + Mg → 2Cu + MgBr2

287g of CuBr were consumed by 24g of Mg.

Therefore, Xg of CuBr will be consume by 6.072g of Mg i.e

Xg of CuBr = (287x6.072)/24

Xg of CuBr = 72.611g

Therefore, 72.611g of CuBr is consumed by 0.253 mole of magnesium

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3 years ago
Write the balanced chemical equation between H2SO4H2SO4 and KOHKOH in aqueous solution. This is called a neutralization reaction
const2013 [10]

Answer:

0.185M sulfuric acid

Explanation:

Based on the reaction:

H₂SO₄ + 2KOH → K₂SO₄ + 2H₂O

<em>1 mole of sulfuric acid reacts with 2 moles of KOH</em>

Initial moles of H₂SO₄ and KOH are:

H₂SO₄: 0.750L ₓ (0.470mol / L) = <em>0.3525 moles of H₂SO₄</em>

KOH: 0.700L ₓ (0.240mol / L) = <em>0.168 moles of KOH</em>

The moles of sulfuric acis that react with KOH are:

0.168mol KOH ₓ (1 mole H₂SO₄ / 2 moles KOH) = 0.0840 moles of sulfuric acid.

Thus, moles that remain are:

0.3525moles - 0.0840 moles = <em>0.2685 moles of sulfuric acid remains</em>

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3 years ago
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