1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Troyanec [42]
3 years ago
11

10. Copper(i) bromide reacts with magnesium metal: 2 CuBr + Mg → 2 Cu + MgBrz

Chemistry
2 answers:
velikii [3]3 years ago
5 0

Answer:

72.6 grams

Explanation:

I got this answer through stoichiometry.  For every 1 mole of Mg, 2 moles of CuBr are consumed.  Because of this, multiply the moles of Mg by 2.  Then, convert moles to grams.

Inessa05 [86]3 years ago
3 0

Answer:

72.611g

Explanation:

Step1:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

2CuBr + Mg → 2Cu + MgBr2

Step 2:

Let us calculate the mass of Mg in 0.253 mole of Mg. This is illustrated below:

Molar Mass of Mg = 24g/mol

Mole of Mg = 0.253 mole

Mass of Mg =?

Mass = number of mole x molar Mass

Mass of Mg = 0.253 x 24

Mass of Mg = 6.072g

Step 3:

Let us calculate the mass of CuBr and the mass of Mg that reacted from the balanced equation. This is illustrated below:

Molar Mass of CuBr = 63.5 + 80 = 143.5g/mol

Mass of CuBr from the balanced equation above = 2 x 143.5 = 287g

Molar Mass of Mg = 24g/mol

Step 4:

The mass of CuBr consumed by 0.253 mole ( i.e 6.072g) of Mg can be obtained as follow:

From the balanced equation:

2CuBr + Mg → 2Cu + MgBr2

287g of CuBr were consumed by 24g of Mg.

Therefore, Xg of CuBr will be consume by 6.072g of Mg i.e

Xg of CuBr = (287x6.072)/24

Xg of CuBr = 72.611g

Therefore, 72.611g of CuBr is consumed by 0.253 mole of magnesium

You might be interested in
Calculate the how many sodium atoms must react completely to give 33,6 dm³ hydro-
lions [1.4K]

To give 33.6 dm³ hydrogen gas at STP, 18.06 x 10²³ atoms of Na must react completely.

<h3>What is Mole concept ?</h3>

A mole is a unit of measurement used to measure the amount of any fundamental entity (atoms, molecules, ions) present in the substance.

As according to the given equation, 2 moles (ie 12.04 x 10²³ atoms) of Na-atoms produces 1 mole (22.4 ltr) of H₂-gas.

Hence, to produce 33.6 ltr (equivalent to 33.6 dm³) of H₂-gas produced by ;

   = 12.04 x 10²³ atoms of Na / 22.4 ltr of H₂-gas x 33.6 ltr

   = 18.06 x 10²³ atoms of Na

Hence, To give 33.6 dm³ hydrogen gas at STP, 18.06 x 10²³ atoms of Na must react completely.

Learn more about Mole concept here ;

brainly.com/question/20483253

#SPJ1

8 0
2 years ago
60 POINTS + BRAINLIEST !! PLEASE HELP!!
uranmaximum [27]
To get moles. divide mass by molar mass.Molar mass of
Na is 23
and for Cl is 35.5.
the total molar mass of NaCl is 23+35.5 = 58.5mol/gUse the mass and divide by this number30.22g divide by 58.5mol/g and you will get 0.5166 mole.
Since the molecule has 1 Na to 1 Cl, and that the number of moles for NaCL is 0.5166. All of them would be 0.5166molesNa = 0.5166 x 1 = 0.5166molesCl = 0.5166 x 1 = 0.5166moles
to get number of atoms. Multiply your mole by Avogadro number which is 6.022x10^23Na = 0.5166 x 6.022E23 = 3.111x10^23Cl =  0.5166 x 6.022E23 = 3.111x10^23
5 0
4 years ago
At what point is a base no longer added during a titration?
nordsb [41]

Answer:

when the pH increases suddenly in the flask

Explanation:

I think it's right. :)

6 0
3 years ago
Read 2 more answers
Given the reaction _K(s) +_ Cl2(g) → _KCl(s) what is the amount of K, in grams, needed to completely react with 2 moles of Cl2(g
damaskus [11]

Answer:

156.4g K

Explanation:

I'm not sure if it is correct but I think it should be this

What do we know so far?: 2K + 1Cl2 -> 2KCl, 2 mol of Cl2

What are we looking for?: #g of K

What is the ratio of K to Cl2?: 2:1

Set up equation: 2molCl2 x \frac{2mol K}{1 mol Cl2}

Cancel unwanted units: 2 x \frac{2mol K}{1}

Answer we got: 2 x 2mol K = 4mol K

Converting moles to grams: 4 x 39.1 (molar mass of K) = 156.4g K

3 0
3 years ago
Louisa put a bowl of water and a bowl of sand in the sun. She put a thermometer in each bowl. Then she recorded the temperature
Helen [10]

The experiment that was carried out by Louisa goes to show us that different materials heat up at different rates.

<h3>What is the specific heat capacity?</h3>

The term specific heat capacity just goes to show us the amount of heat that must be absorbed before the temperature of an object would rise by 1 K. In this case, we can see that we have been told that the after 30 minutes, the sand had heated more than the water. This simply implies that the energy that the sand and the water absorbed was able to increase the temperature of the sand mush more than it increased the temperature of the water.

Thus we can see that the heat capacity of the sand is much less than the heat capacity of the water since the sand could be able to be heated up much faster than the the water could be heated up.

Learn more about heat capacity:brainly.com/question/28302909

#SPJ1

8 0
1 year ago
Other questions:
  • How much heat energy is required to melt 337.1 g of HBr? The molar heat of fusion of HBr is 2.41 kJ/mol.
    13·2 answers
  • What substance is acting as the Brønsted-Lowry base in the forward reaction below? H2O + HCl yields H3O+ + Cl-
    14·1 answer
  • Which of these is a base? a-vinegar b-ammonia c-HCl d- HNO3
    5·2 answers
  • Salt water can be desalinated by distillation. How much energy is needed to convert 175 g of salt water at 28.0 °C to water vapo
    9·1 answer
  • What is tins atomic symbol
    12·2 answers
  • Debscribe each of the following with the correct term
    5·1 answer
  • 20 POINTS!!!
    10·1 answer
  • 9. Which is a product of photosynthesis?
    14·1 answer
  • Upon combustion, a compound containing only carbon and hydrogen produces 2.67 g<img src="https://tex.z-dn.net/?f=CO_%7B2%7D" id=
    13·1 answer
  • Aluminium reacts with sulfuric acid to form aluminium sulfate and hydrogen. What is the volume of
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!